我如何实现ListView
具有Dismissible
小部件的a ,并且当我滑动时,我可以删除该项目,但是如何在点击 say aSnackBar
的操作时将其恢复。谁能给我举个例子?这是我在State
课堂上的情况。
List<String> _list = List.generate(10, (index) => "${index}");
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(title: Text("App")),
body: ListView.builder(
itemCount: _list.length,
itemBuilder: (context, index) {
return Dismissible(
key: Key(_list[index]),
background: Container(color: Colors.red,),
child: ListTile(title: Text(_list[index])),
onDismissed: (direction) => setState(() => _list.removeAt(index))
);
},
)
);
}
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Cop*_*oad 12
所有你需要的是
_list.insert(index, yourDeletedItem);
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这是SnackBar
添加的完整代码。
GlobalKey<ScaffoldState> _key = GlobalKey(); // added
List<String> _list = List.generate(10, (index) => "${index}");
@override
Widget build(BuildContext context) {
return Scaffold(
key: _key, // added
appBar: AppBar(title: Text("App")),
body: ListView.builder(
itemCount: _list.length,
itemBuilder: (context, index) {
return Dismissible(
key: Key(_list[index]),
child: ListTile(title: Text(_list[index])),
background: Container(color: Colors.red),
onDismissed: (direction) {
setState(() {
// added this block
String deletedItem = _list.removeAt(index);
_key.currentState
..removeCurrentSnackBar()
..showSnackBar(
SnackBar(
content: Text("Deleted \"${deletedItem}\""),
action: SnackBarAction(
label: "UNDO",
onPressed: () => setState(() => _list.insert(index, deletedItem),) // this is what you needed
),
),
);
});
},
);
},
),
);
}
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