每天只获得TSQL中的多个条目的最后一行

Question

我有一张桌子,类似于:

Id        Name        EnteredOn                    Percentage
`````````````````````````````````````````````````````````````
01        person1     2011-03-09 17:29:35.683      56.29
02        person1     2011-03-09 17:29:35.731      76.29
03        person1     2011-03-09 18:15:78.683      56.29
04        person1     2011-03-10 17:29:35.683      56.29
05        person1     2011-03-10 16:29:31.683      56.29
06        person1     2011-03-11 17:29:35.683      56.29

总结上面的表格,有3排了一天09和2行白天10.

现在,我只想选择最新的行 - 每行一行.
(一行为9,一行为10,一行为11)

由于时间戳,我不能使用distinct.我不能分组并使用:

CAST(CONVERT(FLOAT, EnteredOn) AS INT)

因为当我选择EnteredOn字段时,它会抱怨它没有分组.我无法合并distinct(cast..date...)因为我无法获得正确的语法.

我如何选择 - 只有Name,EnteredOn,Percentage字段与每天不同？

提前谢谢了.

Answer 1

;with cte as
(
  select
    *,
    row_number() over(partition by datediff(d, 0, EnteredOn) order by EnteredOn desc) as rn 
  from YourTable
)
select *
from cte  
where rn = 1

Answer 2

1行/天:

SELECT t1.Name, t1.EnteredOn, t1.Percentage
  FROM table t1
  JOIN (SELECT MAX(EnteredOn) Max_EnteredOn_By_Day
          FROM table 
         GROUP BY convert(varchar, EnteredOn, 112)) t2
  ON t1.EnteredOn = t2.Max_EnteredOn_By_Day

1行/人/天:

SELECT t1.Name, t1.EnteredOn, t1.Percentage
  FROM table t1
  JOIN (SELECT Name, MAX(EnteredOn) Max_EnteredOn_By_Day
          FROM table 
         GROUP BY Name, convert(varchar, EnteredOn, 112)) t2
  ON t1.Name = t2.Name
 AND t1.EnteredOn = t2.Max_EnteredOn_By_Day

Answer 3

SELECT Name, EnteredOn, Percentage
FROM (  SELECT *, ROW_NUMBER() OVER(PARTITION BY CONVERT(VARCHAR(8),EnteredOn,112) ORDER BY EnteredOn DESC) Corr
        FROM YourTable) A
WHERE Corr = 1