Camel Rest DSL 检索 HTTP POST 多部分文件

Question

我的路由器类如下所示，我正在尝试上传视频文件并将其存储到文件位置。

SpringBootRouter.java

package com.camelrest;

import java.util.HashMap;
import java.util.Map;

import org.apache.camel.component.restlet.RestletComponent;
import org.apache.camel.spring.boot.FatJarRouter;
import org.restlet.Component;
import org.restlet.ext.spring.SpringServerServlet;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.embedded.ServletRegistrationBean;
import org.springframework.context.annotation.Bean;

@SpringBootApplication
public class MySpringBootRouter extends FatJarRouter {

    @Autowired
    private MultipartProcessor multipartProcessor;

    @Override
    public void configure() {

        restConfiguration().component("restlet");

        rest("/upload").post().to("direct:upload");

        from("direct:upload")
        .to("file://E:/RestTest");

    }

    @Bean
    public ServletRegistrationBean servletRegistrationBean() {

        SpringServerServlet serverServlet = new SpringServerServlet();
        ServletRegistrationBean regBean = new ServletRegistrationBean(
                serverServlet, "/rest/*");

        Map<String, String> params = new HashMap<String, String>();

        params.put("org.restlet.component", "restletComponent");

        regBean.setInitParameters(params);

        return regBean;
    }

    @Bean
    public Component restletComponent() {
        return new Component();
    }

    @Bean
    public RestletComponent restletComponentService() {
        return new RestletComponent(restletComponent());
    }    
}

我正在尝试使用邮递员上传视频文件，如下图所示：

我上传的文件的内容以文件名保存，其中包含一些由骆驼生成的随机骆驼 ID

但是我想要在正文中传递的文件名

SampleVideo_1280x720_10mb.mp4

成为文件名并从正文中删除以下内容

----------------------------948281627232093197119960
Content-Disposition: form-data; name="file"; filename="SampleVideo_1280x720_10mb.mp4"
Content-Type: video/mp4

所以最终输出可以是使用邮递员上传时使用的文件名上传的视频

Answer 1

您可以使用MimeMultipartDataFormat解组 Multipart 请求。使用这个，将准备附件，到Exchange.

之后，您需要以某种方式转换Attachment为InputStream并填充CamelFileName标题。有了这个任务可以帮你小Processor。

路线：

from("direct:upload")
        .unmarshal().mimeMultipart().split().attachments()
        .process(new PrepareFileFromAttachment())
        .to("file://C:/RestTest");

处理器：

class PrepareFileFromAttachment implements Processor {
    @Override
    public void process(Exchange exchange) throws Exception {
        DataHandler dataHandler = exchange.getIn().getBody(Attachment.class).getDataHandler();
        exchange.getIn().setHeader(Exchange.FILE_NAME, dataHandler.getName());
        exchange.getIn().setBody(dataHandler.getInputStream());
    }
}

如果您的表单仅包含表单中的单个输入，则上述方法不起作用。这是因为MimeMultipartDataFormat编组首先将输入表单输入到正文（不存储文件名）和其他输入到存储文件名的附件中。在这种情况下，您需要直接创建Processor阅读InputStream：

路线：

from("direct:upload")
        .process(new ProcessMultipartRequest())
        .to("file:c://RestTest");

处理器

public class ProcessMultipartRequest implements Processor {
    @Override
    public void process(Exchange exchange) throws Exception {
        InputStream is = exchange.getIn().getBody(InputStream.class);
        MimeBodyPart mimeMessage = new MimeBodyPart(is);
        DataHandler dh = mimeMessage.getDataHandler();
        exchange.getIn().setBody(dh.getInputStream());
        exchange.getIn().setHeader(Exchange.FILE_NAME, dh.getName());
    }
}