fetch() 中的 Async/Await 如何处理错误

Question

我的 React 应用程序中有条带异步代码，并尝试在我的代码中添加错误处理，但不知道如何处理它。我知道如何使用 .then() 但 async/await 对我来说是新的

已编辑

添加了 .catch() 我在响应选项卡的网络选项卡中出错。但我可以将它记录到控制台吗？

    submit = async () => {
    const { email, price, name, phone, city, street, country } = this.state;
    let { token } = await this.props.stripe
      .createToken({
        name,
        address_city: city,
        address_line1: street,
        address_country: country
      })
      .catch(err => {
        console.log(err.response.data);
      });

    const data = {
      token: token.id,
      email,
      price,
      name,
      phone,
      city,
      street,
      country
    };

    let response = await fetch("/charge/pay", {
      method: "POST",
      headers: {
        "Content-Type": "application/json"
      },
      body: JSON.stringify(data)
    }).catch(err => {
      console.log(err.response.data);
    });
    console.log(response);
    if (response.ok)
      this.setState({
        complete: true
      });
  };

谢谢

Answer 1

Fetch 只检测网络错误。其他错误（401、400、500）应手动捕获并拒绝。

await fetch("/charge/pay", headers).then((response) => {
    if (response.status >= 400 && response.status < 600) {
      throw new Error("Bad response from server");
    }
    return response;
}).then((returnedResponse) => {
   // Your response to manipulate
   this.setState({
     complete: true
   });
}).catch((error) => {
  // Your error is here!
  console.log(error)
});

如果您对 fetch 的这种限制不满意，请尝试使用 axios。

Answer 2

var handleError = function (err) {
    console.warn(err);
    return new Response(JSON.stringify({
        code: 400,
        message: 'Stupid network Error'
    }));
};

var getPost = async function () {

    // Get the post data
    var post = await (fetch('https://jsonplaceholder.typicode.com/posts/5').catch(handleError));

    // Get the author
    var response = await (fetch('https://jsonplaceholder.typicode.com/users/' + post.userId).catch(handleError));

       if (response.ok) {
            return response.json();
        } else {
            return Promise.reject(response);
        }

};

Answer 3

您可以像普通的命令式编程一样使用try/ catch：

try {
    let response = await fetch("/charge/pay", {
      method: "POST",
      headers: {
          "Content-Type": "application/json"
      },
      body: JSON.stringify(data)
    });
} catch(error) {
    // Error handling here!
}

或者你可以.catch()像使用 promise 一样混合搭配：

let response = await fetch("/charge/pay", {
    method: "POST",
    headers: {
       "Content-Type": "application/json"
    },
    body: JSON.stringify(data)
}).catch(function(error) {
    // Error handling here!
});

Answer 4

如果服务器返回，这会起作用{ message: "some error" }，但我也试图让它支持res.statusText：

        const path = '/api/1/users/me';
        const opts = {};
        const headers = {};
        const body = JSON.stringify({});
        const token = localStorage.getItem('token');

        if (token) {
          headers.Authorization = `Bearer ${token}`;
        }

        try {
            const res = await fetch(path, {
                method: opts.method || 'GET',
                body,
                headers
            });

            if (res.ok) {
                return await (opts.raw ? res.text() : res.json());
            }

            const err = await res.json();

            throw new Error(err.message || err.statusText);
        } catch (err) {
            throw new Error(err);
        }

Answer 5

用 try catch 包裹你的等待。

try {
    let response = await fetch("/charge/pay", {
      method: "POST",
      headers: {
        "Content-Type": "application/json"
      },
      body: JSON.stringify(data)
    });

    console.log(response);
} catch (error) {
    console.log(error);
}