正则表达从10000到1800000

Question

我需要检查字符串是否包含10000到1800000之间的数字.

我带来了以下正则表达式:

^[1-9][0-9]{4}$|^[0-9]{6}$|^1[0-7][0-9]{5}$|^1800000$+

---

是否有更好或更优化的方式来执行它？

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const regex = /^[1-9][0-9]{4}$|^[0-9]{6}$|^1[0-7][0-9]{5}$|^1800000$/;

const mustFailTests = [
  '9999',
  '15',
  '00015',
  '-15000',
  '1800001',
  '9000000',
  '0',
  '',
];

const mustWorkTests = [
  '10000',
  '1800000',
  '200000',
  '25018',
  '778410',
  '1000000',
  '1205900',
];

const start = Date.now();

mustFailTests.forEach((x) => {
  const ret = regex.test(x);

  console.log(`${x} must fail : result ${ret}`);
});

console.log('--------------------------------');

mustWorkTests.forEach((x) => {
  const ret = regex.test(x);

  console.log(`${x} must succeed : result ${ret}`);
});

for (let i = 0; i < 500000; i += 1) {
  mustWorkTests.forEach(x => regex.test(x));
  mustFailTests.forEach(x => regex.test(x));
}

console.log(`It took ${Date.now() - start} ms`);

Answer 1

为什么不将该字符串转换为数字并与您需要的字符串进行比较

const validate = (input) => 10000 <= +input && 1800000 >= +input