vgv*_*113 1 api json nsdictionary ios swift
我对json解析非常陌生,并尝试解析具有汽车列表的json文件,但是当我解析时,它给出nil
func jsonTwo(){
let url = Bundle.main.url(forResource: "car_list", withExtension: "json")!
let data = try! Data(contentsOf: url)
let JSON = try! JSONSerialization.jsonObject(with: data, options: []) as? [String : Any]
print(".........." , JSON , ".......")
let brand = JSON?["models"] as? [[String : Any]]
print("=======",brand,"=======")
}
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当我如下修改此代码时
func jsonTwo(){
let url = Bundle.main.url(forResource: "car_list", withExtension: "json")!
let data = try! Data(contentsOf: url)
let JSON = try! JSONSerialization.jsonObject(with: data, options: [])
print(".........." , JSON , ".......")
let brand = JSON["brand"] as? [[String : Any]]
print("=======",brand,"=======")
}
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然后我得到错误提示“ Type'Any'没有下标成员”
以下是我正在使用的json文件的示例
[{"brand": "Aston Martin", "models": ["DB11","Rapide","Vanquish","Vantage"]}]
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外部对象是一个数组,请注意,[]并且key的值models是一个String数组。
func jsonTwo() {
let url = Bundle.main.url(forResource: "car_list", withExtension: "json")!
let data = try! Data(contentsOf: url)
let json = try! JSONSerialization.jsonObject(with: data) as! [[String : Any]]
print(".........." , JSON , ".......")
for item in json {
let brand = item["brand"] as! String
let models = item["models"] as! [String]
print("=======",brand, models,"=======")
}
}
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或更满意 Decodable
struct Car: Decodable {
let brand : String
let models : [String]
}
func jsonTwo() {
let url = Bundle.main.url(forResource: "car_list", withExtension: "json")!
let data = try! Data(contentsOf: url)
let cars = try! JSONDecoder().decode([Car].self, from: data)
for car in cars {
let brand = car.brand
let models = car.models
print("=======",brand, models,"=======")
}
}
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通常,强烈建议不要使用强制解开可选选项,!但是在这种情况下,代码不得崩溃,因为应用程序捆绑包中的文件在运行时是只读的,任何崩溃都可能显示设计错误。
你需要
struct Root: Codable {
let brand: String
let models: [String]
}
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do {
let url = Bundle.main.url(forResource: "car_list", withExtension: "json")!
let data = try Data(contentsOf: url)
let res = try JSONDecoder().decode([Root].self, from: data)
print(res)
}
catch {
print(error)
}
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你的问题是
let JSON = try! JSONSerialization.jsonObject(with: data, options: [])
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返回Any,所以你不能在这里像字典一样使用下标JSON["brand"]
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