如何在没有数组的情况下连续比较N对整数

Question

这是一个检查共素对的程序.

我正在尝试编写一个程序来接收整数输入,直到用户输入0,这很容易在数组的帮助下解决(我已经用数组做了)因为一次只能读取一个值并检查.使用数组它只是:

for(i = 0; i < n-1; i++)

然后比较v[i]和v[i+1]

我试图在没有数组的情况下应用这种精确的检查算法,但是,读取两个值并比较它们,不知何故,只有当我多次输入0,有时两次,有时三次时,循环才会结束.

#include <stdio.h>


int gcd1(int a, int b) //function containing Euclid's algorithm 
{
    while (b != 0)
    {
        int temp = a%b;

        a = b;
        b = temp;
    }


    return a;   
}


int main(int argc, char * argv[])
{

    int num1, num2; /* both of these vars would otherwise have a non-zero 
    value if I was using Try Nr.1 written in bold below was applied */

    int cate = 0, flag = 1;
    while(1)
    {
        scanf("%d %d", &num1, &num2);

        if(num1 == 0 && num2 == 0)
        {
        break;
        }

        if(gcd1(num1, num2) == 1) //check if pair is co-prime 
        {
            cate++;
        }

    }
        printf("%d\n", cate);


    return 0;
}

我试过的事情:

1 -

while(num1 != 0 || num2 != 0) /*using this inside the while(), also tried
changing the operator to &&, without a condition and a break inside the 
body*/

2 -

尝试了while(flag != 0)改变if(num1 == 0 || num2 == 0),改变了操作员,&&但它仍然是相同的,或者对我没有意义.

我需要的程序是在任何输入0处停止,例如:

25 27 12 24 11 13 0 

程序应该停在那里并告诉我有多少对是共同素数但它只在我再输入0两次时停止.

如果需要,我将发布使用数组完成的那个.

编辑

我根据布鲁诺的答案从下面更新了程序,进行了一些测试,未通过问题提供的测试.

#include <stdio.h>


int gcd1(int a, int b) //function containing Euclid's algorithm 
{
    while (b != 0)
    {
        int temp = a%b;

        a = b;
        b = temp;
    }


    return a;   
}


int main(int argc, char * argv[])
{

    int num1, num2; /* both of these vars would otherwise have a non-zero 
    value if I was using Try Nr.1 written in bold below was applied */

    int cate = 0, flag = 1;
    while(1)
    {
        scanf("%d %d", &num1, &num2);

        if(num1 == 0 && num2 == 0)
        {
        break;
        }

        if(gcd1(num1, num2) == 1) //check if pair is co-prime 
        {
            cate++;
        }

    }
        printf("%d\n", cate);


    return 0;
}

输入:

while(num1 != 0 || num2 != 0) /*using this inside the while(), also tried
changing the operator to &&, without a condition and a break inside the 
body*/

输出for(i = 0; i < n-1; i++)是正确的,v[i]并且v[i+1]是共同素数对.

但是输入:

25 27 12 24 11 13 0 

输出while(flag != 0)但应该是if(num1 == 0 || num2 == 0).

Answer 1

我需要的程序是在任何输入0停止

scanf("%d %d", &num1, &num2); 在您输入2个数字之前阻塞

如果要在第一个数字为0时停止而不必读取第二个数字,则必须执行2次扫描

scanf("%d", &num1);

if(num1 == 0)
  break;

scanf("%d", &num2);

if(num2 == 0)
  break;