MrP*_*ink 8 iphone cocoa-touch objective-c ios4 ios
基本上我有一个返回的XML响应和一个字符串,我需要遍历xml并将所有信息存储在一个数组中.这是xml
<?xml version="1.0" encoding="UTF-8"?>
<Response xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://schema.2sms.com/2.0/schema/0310_ResponseReportStandard.xsd" Version="1.0">
<Error>
<ErrorCode>00</ErrorCode>
<ErrorReason>OK</ErrorReason>
</Error>
<ResponseData>
<Identification>
<UserID>jonathan.pink@2sms.com</UserID>
</Identification>
<Result>2 records were returned</Result>
<Detail>
<ReportTitle>Message Summary: Today</ReportTitle>
<Record>
<Destination>447790686158</Destination>
<Status>WithNetwork</Status>
<GUID><![CDATA[2011-03-22T10:54:22.097Z]]></GUID>
<DateSubmitted>2011-03-22T10:54:22.097</DateSubmitted>
<DateToSend></DateToSend>
<DateSent>2011-03-22T10:54:22.533</DateSent>
<DateReceived></DateReceived>
<Message><![CDATA[Yet again another test]]></Message>
<ID>2011-03-22 10:54:22.250HIHIIOJTFVETW85TS</ID>
</Record>
<Record>
<Destination>447790686158</Destination>
<Status>SUCCESS</Status>
<GUID><![CDATA[2011-03-22T10:50:40.064Z]]></GUID>
<DateSubmitted>2011-03-22T10:50:40.063</DateSubmitted>
<DateToSend></DateToSend>
<DateSent>2011-03-22T10:50:42.473</DateSent>
<DateReceived>2011-03-22T10:50:54.570</DateReceived>
<Message><![CDATA[This is a test]]></Message>
<ID>2011-03-22 10:50:40.210DRUDVMCEZGETW85TS</ID>
</Record>
<ReportPage ReportID="775797" ItemsPerPage="25" Page="1" TotalItems="2" />
</Detail>
</ResponseData>
</Response>
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我需要那些2 <records>和所有数据存储在一个数组中.所以....
记录数组 - >记录数组 - >每个记录的数组,数据....
我一直坐在这里试图使用TBXML来解决这个问题,这很容易抓住一个节点....但我不能这样做:(
sud*_*-rf 14
好吧,你的第一步是创建一个解析数据的类.RecordParser例如,打电话给它.我们现在需要在标题中添加几个方法,以及a NSMutableArray.
@interface RecordParser : NSObject {
NSMutableArray *records;
}
@property(nonatomic,retain)NSMutableArray *records;
-(void)loadRecords:(NSString *)records;
-(void)traverseElement:(TBXMLElement *)element;
@end
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现在,继续并充实您的实施.我们现在需要实现这两种方法来完成我们希望他们做的事情.
- (void)loadRecords:(NSString *)records {
NSString *someXML = @"http://www.something.com/somexml.xml";
TBXML *tbxml = [[TBXML tbxmlWithURL:[NSURL URLWithString:someXML]] retain];
records = [NSMutableArray array];
[records retain];
if (tbxml.rootXMLElement)
[self traverseElement:tbxml.rootXMLElement];
[tbxml release];
}
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基本上该方法将获取有问题的XML文件并开始解析过程.此外,您正在初始化阵列并保留它.现在我们来看看奶酪吧.
- (void) traverseElement:(TBXMLElement *)element {
do {
if (element->firstChild)
[self traverseElement:element->firstChild];
if ([[TBXML elementName:element] isEqualToString:@"Record"]) {
TBXMLElement *destination = [TBXML childElementNamed:@"Destination" parentElement:element];
TBXMLElement *status = [TBXML childElementNamed:@"Status" parentElement:element];
TBXMLElement *guid = [TBXML childElementNamed:@"GUID" parentElement:element];
TBXMLElement *dateSub = [TBXML childElementNamed:@"DateSubmitted" parentElement:element];
TBXMLElement *dateToSend = [TBXML childElementNamed:@"DateToSend" parentElement:element];
TBXMLElement *dateSent = [TBXML childElementNamed:@"DateSent" parentElement:element];
TBXMLElement *dateReceived = [TBXML childElementNamed:@"DateReceived" parentElement:element];
TBXMLElement *message = [TBXML childElementNamed:@"Message" parentElement:element];
TBXMLElement *id = [TBXML childElementNamed:@"ID" parentElement:element];
[records addObject:[NSArray arrayWithObjects:
[TBXML textForElement:destination],
[TBXML textForElement:status],
[TBXML textForElement:guid],
[TBXML textForElement:dateSub],
[TBXML textForElement:dateToSend],
[TBXML textForElement:dateSent],
[TBXML textForElement:dateReceived],
[TBXML textForElement:message],
[TBXML textForElement:id],nil]];
}
} while ((element = element->nextSibling));
}
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基本上该方法所做的是横向XML文件寻找具有您正在寻找的名称的元素,然后它从子节点获取数据.此外,数据将添加到records阵列中.所以基本上,当它完成时,它应该拥有你想要的数据records,你可以操纵你想要的所有数据.
这是完全未经测试的.如果它炸毁你的电脑并杀死你的猫,不要怪我.我通常不会把所有的工作都写成这样一个完整的方法,但我碰巧喜欢TBXML.如果有效,请告诉我.我真的很感激知道.
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