async/await 不适用于 mongo DB 查询

Question

工作案例：

当我们调用异步函数并且该函数返回承诺 resolve() 时，异步等待工作正常

不工作的情况：

异步等待不适用于 mongo DB 查询

试过 then(), async/await

我有 2 个 JS 文件。

在 one.js 文件中，我正在导入 functionone.js 中的函数

工作案例：

当 one.js 看起来像

var functiononestatus = transactions.functionone(req.session.email).then((came) => {
  console.log(came); // getting `need to be done at first` message
  console.log("exec next")
});

当 functionone.js 看起来像

module.exports.functionone = functionone;

async function functionone(email) {
  return await new Promise((resolve, reject) => {
    resolve('need to be done at first')
  });
});

非工作情况（当需要执行 mongo db 查询时）：

当 one.js 看起来像

var functiononestatus = transactions.functionone(req.session.email).then((came) => {
  console.log(came); // getting undefined
  console.log("exec next")
});

当 functionone.js 看起来像

module.exports.functionone = functionone;

async function functionone(email) {

  //mongo starts
  var collection = await connection.get().collection('allinonestores');
  await collection.find({
    "email": email
  }).toArray(async function(err, wallcheck) {
    return await new Promise((resolve, reject) => {
      resolve(wallcheck[0])
    });
  });

Answer 1

快速澄清：

1. .collection('name')返回一个Collection实例，而不是一个 Promise，所以不需要await它。
2. toArray() 以两种模式运行：要么在提供函数时使用回调，要么在未提供回调函数时返回 Promise。

toArray()在提供回调函数时，您本质上是在期待 Promise 结果，结果是undefined，因为由于 toArray() 的双重操作模式，回调优先并且没有返回任何承诺。

此外，toArray(callback)不将async函数作为回调。

以下是用于检索集合的代码的外观：

const client = await MongoClient.connect('your mongodb url');
const db = client.db('your database name'); // No await here, because it returns a Db instance.
const collection = db.collection('allinonestores'); // No await here, because it returns a Collection instance.

然后，获取结果的代码：

const db = <get db somehow>;

// You could even ditch the "async" keyword here,
// because you do not do/need any awaits inside the function.
// toArray() without a callback function argument already returns a promise.
async function functionOne(email) {

  // Returns a Collection instance, not a Promise, so no need for await.
  const collection = db.collection('allinonestore');

  // Without a callback, toArray() returns a Promise.
  // Because our functionOne is an "async" function, you do not need "await" for the return value.
  return collection.find({"email": email}).toArray();
}

和代码替代，使用回调：

const db = <get db somehow>;

// You could even ditch the "async" keyword here,
// because you do not do/need any awaits inside the function.
// You're forced to return a new Promise, in order to wrap the callback
// handling inside it
async function functionOne(email) {

  // Returns a Collection instance, not a Promise, so no need for await.
  const collection = db.collection('allinonestore');

  // We need to create the promise outside the callback here.
  return new Promise((resolve, reject) => {
    db.find({"email": email}).toArray(function toArrayCallback(err, documents) {
       if (!err) {
         // No error occurred, so we can solve the promise now.
         resolve(documents);
       } else {
         // Failed to execute the find query OR fetching results as array someway failed.
         // Reject the promise.
         reject(err);
       }
    });
  });
}