通过最接近x的值对对象数组进行排序

Question

我有一个对象数组,我想通过最接近X的值对该数组进行排序.

例如,这是一个对象数组:

[
 {"name" : "some 1", "value" : 12.4},
 {"name" : "some 2", "value": 11.4},
 {"name" : "some 3", "value": 10.5},
 {"name" : "some 4", "value": 11.4}
]

我想通过最接近X的"值"对其进行排序.

假设我想对数组进行排序,使属性"value"最接近11.所以新的顺序如下:

[
  {"name" : "some 2", "value": 11.4},
  {"name" : "some 4", "value": 11.4},
  {"name" : "some 3", "value": 10.5},
  {"name" : "some 1", "value": 12.4}
 ]

因为11.4最接近11,然后是10.5然后是12.4.

Answer 1

您可以按值的绝对增量和所需值进行排序.

var array = [{ name: "some 1", value: 12.4 }, { name: "some 2", value: 11.4 }, { name: "some 3", value: 10.5 }, { name: "some 4", value: 11.4 }],
    value = 11;
 
array.sort(({ value: a }, { value: b }) => Math.abs(a - value) - Math.abs(b - value));

console.log(array);

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