use*_*604 5 python plot matplotlib
我想绘制以下场方程:
但我不知道如何将边界限制为三角形x>=0, y>=0, x<=1-y
:
# stream plot with matplotlib
import numpy as np
import matplotlib.pyplot as plt
def velocity_i(x,y):
vx = x*(3*x+4*y-3)
vy = y*(3*x+4*y-4)
return vx, vy
n=100
x = np.linspace(0, 1, n)
y = np.linspace(0, 1, n)
X, Y = np.meshgrid(x, y)
Ux, Uy = velocity_i(X, Y)
vels = (Ux**2+Uy**2)**0.5
plt.figure(figsize=(5,4))
stream = plt.streamplot(X, Y,
Ux,Uy,
arrowsize=1,
arrowstyle='->',
color= vels,
density=1,
linewidth=1,
)
plt.xlabel(r"$\Omega_{\rm m}$",fontsize='14')
plt.ylabel(r"$\Omega_{\rm r}$",fontsize='14')
plt.colorbar(stream.lines)
plt.xlim((-.05,1.05))
plt.ylim((-.05,1.05))
plt.show()
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使用 NumPy 掩码和np.where函数可以非常直接地实现这一点。我仅显示完成工作所需的相关两行代码(通过注释突出显示)。
解释:X<=1-Y
检查所需的边界条件,然后在满足此条件的所有索引处,它分配(或)True
的实际计算值,在条件为 的索引处,它分配 0。这里充当条件掩码。Ux
Uy
False
X<=1-Y
Ux, Uy = velocity_i(X, Y)
Ux = np.where(X<=1-Y, Ux, 0) # <--- Boundary condition for Ux
Uy = np.where(X<=1-Y, Uy, 0) # <--- Boundary condition for Uy
vels = (Ux**2+Uy**2)**0.5
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