Jam*_*mes 0 html javascript css indexing jquery
我们有html代码,如:
<div class="blocks">
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
</div>
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如何得到:
1)前五个要素?
2)可见块的数量(它们可以是不可见的).
3)所有元素的数量?
4)隐形元素的数量?
5)制作可见元素(n)?
6)使来自不可见元素n到n?
n 是一个索引号.
这一切都只对应于.blockdiv.
1)前五个要素?
$('.block:lt("5")'); // zero-based indexing.
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2)可见块的数量(它们可以是不可见的).
$('.block:visible').length; // gets all visible '.block' elements.
$('.block:visible:lt("5")'); // the first five elements
$('.block:visible:gt("2")'); // all elements after the third (zero-based indexing)
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3)所有元素的数量?
$('.block').length;
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4)隐形元素的数量?
$('.block').not(':visible');
$('.block:hidden'); // thanks @strager
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5)制作可见元素(n)?
$('.block').eq(n).show();
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6)从n到n制作不可见元素?
$('.block').each(
function(i){
var lowBound = 2, highBound = 10;
if (i > lowBound && i < highBound) {
$(this).hide();
}
});
$('.block').slice(low, high).hide(); // use this approach, it's much better! Thanks, again, @strager
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