Ric*_*man 6 python scope fixtures pytest
首先,我的项目目录的相关部分如下所示:
??? my_package
??? my_subpackage
? ??? my_module.py
| ??? other_module.py
??? tests
??? my_subpackage
??? unit_test.py
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我正在编写一些测试unit_test.py
,需要在模块级别模拟外部资源。我想使用pytest fixture
模块级范围并pytest monkeypatch
完成此操作。这是我尝试过的片段unit_test.py
:
import unittest.mock as mock
import pytest
from my_package.my_subpackage.my_module import MyClass
@pytest.fixture(scope='function')
def external_access(monkeypatch):
external_access = mock.MagicMock()
external_access.get_something = mock.MagicMock(
return_value='Mock was used.')
monkeypatch.setattr(
'my_package.my_subpackage.my_module.ExternalAccess.get_something',
external_access.get_something)
def test_get_something(external_access):
instance = MyClass()
instance.get_something()
assert instance.data == 'Mock was used.'
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一切正常。但是当我尝试将第 8 行从 更改@pytest.fixture(scope='function')
为 时@pytest.fixture(scope='module')
,出现以下错误。
ScopeMismatch: You tried to access the 'function' scoped fixture 'monkeypatch' with a 'module' scoped request object, involved factories
my_package\tests\unit_test.py:7: def external_access(monkeypatch)
..\..\Anaconda3\envs\py37\lib\site-packages\_pytest\monkeypatch.py:20: def monkeypatch()
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有谁知道如何使用模块级范围进行monkeypatch?
如果有人想知道,这也是这两个模块的样子。
my_module.py
from my_package.my_subpackage.other_module import ExternalAccess
class MyClass(object):
def __init__(self):
self.external_access = ExternalAccess()
self.data = None
def get_something(self):
self.data = self.external_access.get_something()
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other_module.py
class ExternalAccess(object):
def get_something(self):
return 'Call to external resource.'
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Ric*_*man 11
我发现了指导方式的这个问题。我需要对模块级范围的解决方案进行一些更改。unit_test.py
现在看起来像这样:
import unittest.mock as mock
import pytest
from my_package.my_subpackage.my_module import MyClass
@pytest.fixture(scope='module')
def monkeymodule():
from _pytest.monkeypatch import MonkeyPatch
mpatch = MonkeyPatch()
yield mpatch
mpatch.undo()
@pytest.fixture(scope='module')
def external_access(monkeymodule):
external_access = mock.MagicMock()
external_access.get_something = mock.MagicMock(
return_value='Mock was used.')
monkeymodule.setattr(
'my_package.my_subpackage.my_module.ExternalAccess.get_something',
external_access.get_something)
def test_get_something(external_access):
instance = MyClass()
instance.get_something()
assert instance.data == 'Mock was used.'
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从 pytest 6.2 开始,这变得更加简单,这要归功于pytest.MonkeyPatch
类和上下文管理器(https://docs.pytest.org/en/6.2.x/reference.html#pytest.MonkeyPatch)。根据 Rich 的答案,monkeymodule
现在可以将装置编写如下:
@pytest.fixture(scope='module')
def monkeymodule():
with pytest.MonkeyPatch.context() as mp:
yield mp
@pytest.fixture(scope='function')
def external_access(monkeymodule):
external_access = mock.MagicMock()
external_access.get_something = mock.MagicMock(
return_value='Mock was used.')
monkeymodule.setattr(
'my_package.my_subpackage.my_module.ExternalAccess.get_something',
external_access.get_something)
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