从dicts列表中获取"密钥"

Question

我有以下数据:

[{'id': ['132605', '132750', '132772', '132773', '133065', '133150', '133185', '133188', '133271', '133298']}, 
 {'number': ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']}, 
 {'id': ['1', '1', '1', '1', '1', '1', '1', '1', '1', '1']}]

获取密钥列表的最佳方法是什么(好像它是dict而不是数组)？目前我在做:

>>> [list(i.keys())[0] for i in e.original_column_data]
['id', 'number', 'id']

但这感觉有点hackish

Answer 1

什么是hacky呢？它有点不优雅.您只需要执行以下操作:

>>> keys = []
>>> data = [{'id': ['132605', '132750', '132772', '132773', '133065', '133150', '133185', '133188', '133271', '133298']},
...  {'number': ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']},
...  {'id': ['1', '1', '1', '1', '1', '1', '1', '1', '1', '1']}]
>>> for d in data:
...     keys.extend(d)
...
>>> keys
['id', 'number', 'id']

或者如果您更喜欢单行:

>>> [k for d in data for k in d]
['id', 'number', 'id']