使用Spring WebClient解码内容编码gzip

ath*_*hom 3 spring reactor-netty spring-webflux

我正在使用Spring WebClient(Spring 5.1.3)调用Web服务。服务以content-type: application/json和响应content-encoding: gzip

ClientResponse.bodyToMono 然后失败,出现错误“ JSON解码错误:非法字符((CTRL-CHAR,代码31))”,我认为这是因为在尝试解析JSON之前尚未对内容进行解码。

这是我如何创建WebClient的代码段(简化)

HttpClient httpClient = HttpClient.create().secure(sslContextSpec -> sslContextSpec.sslContext(sslContext));
return WebClient.builder().clientConnector(new ReactorClientHttpConnector(httpClient)).build();
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然后,我使用WebClient进行呼叫:

webClient.get().uri(uri)
    .accept(MediaType.APPLICATION_JSON)
    .header(HttpHeaders.ACCEPT_ENCODING, "gzip")
    .exchange()
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HTTP请求具有2个标头:

Accept: application/json
Accept-Encoding: gzip
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响应具有以下标头:

set-cookie: xxx
content-type: application/json; charset=utf-8
content-length: 1175
content-encoding: gzip
cache-control: no-store, no-cache
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通过执行以下操作,我能够手动解码GZIP内容并从结果中获取有效的JSON

webClient.get().uri(uri)
        .accept(MediaType.APPLICATION_JSON)
        .header("accept-encoding", "gzip")
        .exchange()
        .flatMap(encodedResponse -> encodedResponse.body((inputMessage, context) ->
                inputMessage.getBody().flatMap(dataBuffer -> {
                    ClientResponse.Builder decodedResponse = ClientResponse.from(encodedResponse);
                    try {
                        GZIPInputStream gz = new GZIPInputStream(dataBuffer.asInputStream());
                        decodedResponse.body(new String(gz.readAllBytes()));
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                    decodedResponse.headers(headers -> {
                        headers.remove("content-encoding");
                    });
                    return Mono.just(decodedResponse.build());
                }).flatMap(clientResponse -> clientResponse.bodyToMono(Map.class))
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Bri*_*zel 5

反应堆净额客户端本机支持此功能。

您应该这样创建HttpClient

HttpClient httpClient = HttpClient.create()
             .secure(sslContextSpec -> sslContextSpec.sslContext(sslContext))
             .compress(true);
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然后,无需添加接受编码请求标头,因为它已经为您完成。

请注意,当您不提供自定义实例时,此位由连接器本身完成HttpClient