sag*_*uri 4 dart snackbar flutter
我试图显示一个Snackbar点击floatingActionbutton。但是,当我单击时,floatingactionbutton它什么也没有显示。这是我的代码。我正在使用StatefulWidget。我调试并检查了onPressed函数是否也正在执行,但是以某种方式Snackbar不可见。造成此问题的根本原因是什么?我觉得我传递的BuildContext有问题。
class MyApp extends StatefulWidget{
@override
MyAppState createState() {
// TODO: implement createState
return new MyAppState();
}
}
class MyAppState extends State<MyApp>{
File _image;
String _text;
Future getImage() async {
var image = await ImagePicker.pickImage(source: ImageSource.camera);
_image = image;
final FirebaseVisionImage visionImage = FirebaseVisionImage.fromFile(_image);
final TextRecognizer textRecognizer = FirebaseVision.instance.textRecognizer();
final VisionText visionText = await textRecognizer.processImage(visionImage);
String detectedText = visionText.text;
setState(() {
_image = image;
_text = detectedText;
});
}
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
appBar: new AppBar(
title: new Text('Image Picker Example'),
),
body: new Center(
child: _image == null
? new Text('No image selected.')
: new Image.file(_image),
),
floatingActionButton: new FloatingActionButton(
onPressed: (){
showSnackBar(context);
// getImage();
},
tooltip: 'Pick Image',
child: new Icon(Icons.add_a_photo),
),
),
);
}
void showSnackBar(BuildContext context) {
final scaffold = Scaffold.of(context);
final snackBarContent = SnackBar(
content: Text("sagar"),
action: SnackBarAction(
label: 'UNDO', onPressed: scaffold.hideCurrentSnackBar),
);
scaffold.showSnackBar(snackBarContent);
}
}
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小智 10
class MyApp extends StatefulWidget{
@override
MyAppState createState() {
// TODO: implement createState
return new MyAppState();
}
}
class MyAppState extends State<MyApp>{
final GlobalKey<ScaffoldState> _scaffoldkey = new GlobalKey<ScaffoldState>();
File _image;
String _text;
Future getImage() async {
var image = await ImagePicker.pickImage(source: ImageSource.camera);
_image = image;
final FirebaseVisionImage visionImage = FirebaseVisionImage.fromFile(_image);
final TextRecognizer textRecognizer = FirebaseVision.instance.textRecognizer();
final VisionText visionText = await textRecognizer.processImage(visionImage);
String detectedText = visionText.text;
setState(() {
_image = image;
_text = detectedText;
});
}
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
key: _scaffoldkey,
appBar: new AppBar(
title: new Text('Image Picker Example'),
),
body: new Center(
child: _image == null
? new Text('No image selected.')
: new Image.file(_image),
),
floatingActionButton: new FloatingActionButton(
onPressed: (){
showSnackBar();
// getImage();
},
tooltip: 'Pick Image',
child: new Icon(Icons.add_a_photo),
),
),
);
}
void showSnackBar() {
final snackBarContent = SnackBar(
content: Text("sagar"),
action: SnackBarAction(
label: 'UNDO', onPressed: _scaffoldkey.currentState.hideCurrentSnackBar),
);
_scaffoldkey.currentState.showSnackBar(snackBarContent);
}
}
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发生这种情况是因为BuildContext使用的人没有Scaffold祖先,因此将无法找到它来呈现,SnackBar因为Scaffold要显示它。
根据方法文档:
当实际上在同一构建函数中创建了脚手架时,该构建函数的context参数不能用于找到该脚手架(因为它在返回的小部件“上方”)。在这种情况下,可以使用以下带有Builder的技术来为BuildContext提供“在”脚手架下方的新作用域:
Run Code Online (Sandbox Code Playgroud)@override Widget build(BuildContext context) { return Scaffold( appBar: AppBar( title: Text('Demo') ), body: Builder( // Create an inner BuildContext so that the onPressed methods // can refer to the Scaffold with Scaffold.of(). builder: (BuildContext context) { return Center( child: RaisedButton( child: Text('SHOW A SNACKBAR'), onPressed: () { Scaffold.of(context).showSnackBar(SnackBar( content: Text('Hello!'), )); }, ), ); }, ), ); }
解
将其包装FloatingActionButton在Builder小部件中,将比使用GlobalKey@Epizon答案中已经提到过的更加优雅。