INSERT与SELECT

Question

我有一个使用select插入的查询:

INSERT INTO courses (name, location, gid) 
            SELECT name, location, gid 
              FROM courses 
             WHERE cid = $cid

是否可以只为插入选择"名称,位置",并将gid设置为查询中的其他内容？

Answer 1

是的,绝对,但请检查您的语法.

INSERT INTO courses (name, location, gid)
SELECT name, location, 1
FROM   courses
WHERE  cid = 2

当然,您可以放置gid与其位置相同类型的常量,而不仅仅是1.而且,我只是弥补了cid价值.

Answer 2

是的.你可以写 :

INSERT INTO courses (name, location, gid) 
SELECT name, location, 'whatever you want' 
FROM courses 
WHERE cid = $ci

或者您可以从选择的另一个连接中获取值...

Answer 3

正确的语法:选择拼写错误

INSERT INTO courses (name, location, gid)
SELECT name, location, 'whatever you want' 
FROM courses 
WHERE cid = $ci 

Answer 4

当然,你想用什么来做gid？一个静态值,PHP var,...

静态值1234可能是这样的:

INSERT INTO courses (name, location, gid)
SELECT name, location, 1234
FROM courses
WHERE cid = $cid