Ant*_*ony 2 arrays swift decodable encodable
我正在从 API 检索 JSON,并且想为我使用的每个端点创建一个模型。
\n\n所有端点都使用以下格式:
\n\n{\n "id": "xxxxxx",\n "result": {\xe2\x80\xa6},\n "error": null\n}\nRun Code Online (Sandbox Code Playgroud)\n\n关键是:
\n\nid始终是一个字符串error可以为空或包含键的对象result可以为null;一个对象或一个数组。我遇到的问题是,在端点之一上,结果是数组的数组:
\n\n{\n "id": "xxxxxx",\n "result": [\n [\n "client_id",\n "name",\n 50,\n "status"\n ]\n ],\n "error": null\n}\nRun Code Online (Sandbox Code Playgroud)\n\n正如您所看到的,我有数组的数组,其中值可以是字符串或整数。
\n\n如何使用 Decodable 协议对其进行解码,然后根据其原始值将这些解码值用作 String 或 Int ?
\nimport Foundation
let string = """
{
"id": "xxxxxx",
"result": [
[
"client_id",
"name",
50,
"status"
]
],
"error": null
}
"""
struct Container: Codable {
let id: String
let result: [[Result]]
let error: String?
}
enum Result: Codable {
case integer(Int)
case string(String)
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode(Int.self) {
self = .integer(x)
return
}
if let x = try? container.decode(String.self) {
self = .string(x)
return
}
throw DecodingError.typeMismatch(Result.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for Result"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
try container.encode(self)
}
}
let jsonData = string.data(using: .utf8)!
let container = try? JSONDecoder().decode(Container.self, from: jsonData)
print(container)
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改进了@ArinDavoodian 的答案。
读取数据:
container?.result.first?.forEach { object in
switch object {
case let .integer(intValue):
print(intValue)
break
case let .string(stringValue):
print(stringValue)
break
}
}
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一个简单的解决方案:
let yourInsideArray = container?.result.first!
for index in 0..<yourInsideArray.count {
let yourObjectInsideThisArray = yourInsideArray[i]
//do some
switch yourObjectInsideThisArray {
case let .integer(intValue):
print(intValue)
break
case let .string(stringValue):
print(stringValue)
break
}
}
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