我正在尝试使用RestSharp创建一个post请求.
我有以下字符串
"{ \"name\": \"string\", \"type\": \"string\", \"parentId\": \"string\", \"Location\": [ \"string\" ]}"
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我需要将它传递到json主体发送POST请求我正在尝试以下.
public IRestResponse PostNewLocation(string Name, string Type, Nullable<Guid> ParentId, string Locatations)
{
string NewLocation = string.Format("{ \"name\": \"{0}\", \"type\": \"{1}\", \"parentId\": \"{2}\", \"Location\": [ \"{3}\" ]}", Name, Type, ParentId, Location);
var request = new RestRequest(Method.POST);
request.Resource = string.Format("/Sample/Url");
request.AddParameter("application/json", NewLocation, ParameterType.RequestBody);
IRestResponse response = Client.Execute(request);
}
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而错误
Message: System.FormatException : Input string was not in a correct format.
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如何格式化上面的字符串以将其传递到json正文?
我的测试在这一行失败了
string NewLocation = string.Format("{ \"name\": \"{0}\", \"type\": \"{1}\", \"parentId\": \"{2}\", \"Location\": [ \"{3}\" ]}", Name, Type, ParentId, Location);
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您的格式字符串中有开括号,但没有格式项.您可以使用双括号:
// With more properties of course
string newLocation = string.Format("{{ \"name\": \"{0}\" }}", Name);
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......但我强烈建议你不要.相反,使用JSON库生成JSON,例如Json.NET.它非常简单,无论是使用类还是匿名类型.例如:
object tmp = new
{
name = Name,
type = Type,
parentId = ParentId,
Location = Location
};
string json = JsonConvert.SerializeObject(tmp);
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那样: