从哈希数组中过滤重复哈希 - Javascript

Question

我有一系列哈希,像这样:

[{id: "4bf58dd8d48988d110941735", name: "italy"},
 {id: "4bf58dd8d48988d1c6941735", name: "skandi"},
 {id: "4bf58dd8d48988d147941735", name: "diner"},
 {id: "4bf58dd8d48988d110941735", name: "italy"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"},
 {id: "4bf58dd8d48988d14a941735", name: "vietnam"},
 {id: "4bf58dd8d48988d1ce941735", name: "fish"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"}]

我想扔掉重复的哈希.设置不起作用,因为哈希是唯一对象.

我感到困难,需要一脚思考.请指教!

Answer 1

您可以使用减少太

//I added comma to each object
const data= [{id: "4bf58dd8d48988d110941735", name: "italy"},
    {id: "4bf58dd8d48988d1c6941735", name: "skandi"},
    {id: "4bf58dd8d48988d147941735", name: "diner"},
    {id: "4bf58dd8d48988d110941735", name: "italy"},
    {id: "4bf58dd8d48988d1c4941735", name: "resto"},
    {id: "4bf58dd8d48988d14a941735", name: "vietnam"},
    {id: "4bf58dd8d48988d1ce941735", name: "fish"},
    {id: "4bf58dd8d48988d1c4941735", name: "resto"},
    {id: "4bf58dd8d48988d1c4941735", name: "resto"}]

const result= data.reduce((current,next)=>{   
    if(!current.some(a=> a.name === next.name)){
        current.push(next);
    }
    return current;
},[])
console.log(result);

Answer 2

试试这个

h.filter(( t={}, a=>!(t[a.id]=a.id in t) ))

h中输入数组,时间复杂度为O(n),这里有解释.

let h = [{id: "4bf58dd8d48988d110941735", name: "italy"},
 {id: "4bf58dd8d48988d1c6941735", name: "skandi"},
 {id: "4bf58dd8d48988d147941735", name: "diner"},
 {id: "4bf58dd8d48988d110941735", name: "italy"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"},
 {id: "4bf58dd8d48988d14a941735", name: "vietnam"},
 {id: "4bf58dd8d48988d1ce941735", name: "fish"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"},
 {id: "4bf58dd8d48988d1c4941735", name: "resto"}]
 
 let t; // declare t to avoid use global (however works without it too)
 let r= h.filter(( t={}, a=>!(t[a.id]=a.id in t) ))

 
 console.log(JSON.stringify(r));