Ano*_* CH 76
我找到了一个DhcpInfo在android.net包中调用的类.它有一些公共变量存储当前网络参数的值.但问题是它们返回从8Bit移位二进制转换的整数值.
示例图像描述您的场景:

****以下是示例代码:**
**java文件:****
package com.schogini.dhcp;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.widget.TextView;
import android.net.*;
import android.net.wifi.WifiManager;
public class dhcpInfo extends Activity {
public String s_dns1 ;
public String s_dns2;
public String s_gateway;
public String s_ipAddress;
public String s_leaseDuration;
public String s_netmask;
public String s_serverAddress;
TextView info;
DhcpInfo d;
WifiManager wifii;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
wifii= (WifiManager) getSystemService(Context.WIFI_SERVICE);
d=wifii.getDhcpInfo();
s_dns1="DNS 1: "+String.valueOf(d.dns1);
s_dns2="DNS 2: "+String.valueOf(d.dns2);
s_gateway="Default Gateway: "+String.valueOf(d.gateway);
s_ipAddress="IP Address: "+String.valueOf(d.ipAddress);
s_leaseDuration="Lease Time: "+String.valueOf(d.leaseDuration);
s_netmask="Subnet Mask: "+String.valueOf(d.netmask);
s_serverAddress="Server IP: "+String.valueOf(d.serverAddress);
//dispaly them
info= (TextView) findViewById(R.id.infolbl);
info.setText("Network Info\n"+s_dns1+"\n"+s_dns2+"\n"+s_gateway+"\n"+s_ipAddress+"\n"+s_leaseDuration+"\n"+s_netmask+"\n"+s_serverAddress);
}
}
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xml编码:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.schogini.dhcp"
android:versionCode="1"
android:versionName="1.0">
<uses-sdk android:minSdkVersion="4" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".dhcpInfo"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
</manifest>
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我尝试将整数值转换为等效值,但我不能.如果你这样做,你可以回复..再见..
更新:有些如何设法将IP转换为v4格式从整数形式转换为IPv4格式:
public String intToIp(int i) {
return ((i >> 24 ) & 0xFF ) + "." +
((i >> 16 ) & 0xFF) + "." +
((i >> 8 ) & 0xFF) + "." +
( i & 0xFF) ;
}
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IMAGE礼貌:http://www.bennadel.com/blog/1830-Converting-IP-Addresses-To-And-From-Integer-Values-With-ColdFusion.htm
rtc*_*c11 11
不推荐使用Formatter.formatIpAddress(int),我们不想使用弃用的方法吗?
AndroidKid的版本以某种方式逆转,但这应该解决它:
public String intToIp(int addr) {
return ((addr & 0xFF) + "." +
((addr >>>= 8) & 0xFF) + "." +
((addr >>>= 8) & 0xFF) + "." +
((addr >>>= 8) & 0xFF));
}
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资料来源:http://www.devdaily.com/java/jwarehouse/android/core/java/android/net/DhcpInfo.java.shtml
小智 5
格式化ip,尝试使用:
import android.text.format.Formatter;
public String FormatIP(int IpAddress)
{
return Formatter.formatIpAddress(IpAddress);
}
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小智 5
这是一个旧线程,但我找到了android API使用的官方函数(包android.net.NetworkUtils):
/**
* Convert a IPv4 address from an integer to an InetAddress.
* @param hostAddress an int corresponding to the IPv4 address in network byte order
*/
public static InetAddress intToInetAddress(int hostAddress) {
byte[] addressBytes = { (byte)(0xff & hostAddress),
(byte)(0xff & (hostAddress >> 8)),
(byte)(0xff & (hostAddress >> 16)),
(byte)(0xff & (hostAddress >> 24)) };
try {
return InetAddress.getByAddress(addressBytes);
} catch (UnknownHostException e) {
throw new AssertionError();
}
}
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一旦你有了,InetAddress你就可以这样获取格式化的字符串:
intToInetAddress(d.gateway).getHostAddress()
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