mer*_*kle 6 python machine-learning python-3.x scikit-learn sklearn-pandas
我想在函数中使用调整后的 Rsquarecross_val_score。我尝试使用make_scorer功能但它不起作用。
from sklearn.cross_validation import train_test_split
X_tr, X_test, y_tr, y_test = train_test_split(X, Y, test_size=0.2, random_state=0)
regression = LinearRegression(normalize=True)
from sklearn.metrics.scorer import make_scorer
from sklearn.metrics import r2_score
def adjusted_rsquare(y_true,y_pred):
adjusted_r_squared = 1 - (1-r2_score(y_true, y_pred))*(len(y_pred)-1)/(len(y_pred)-X_test.shape[1]-1)
return adjusted_r_squared
my_scorer = make_scorer(adjusted_rsquare, greater_is_better=True)
score = np.mean(cross_val_score(regression, X_tr, y_tr, scoring=my_scorer,cv=crossvalidation, n_jobs=1))
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它抛出一个错误:
IndexError: positional indexers are out-of-bounds
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有什么方法可以使用我的自定义功能,即;adjusted_rsquare和cross_val_score?
adjusted_rsquare(X,Y)是一个数字,它不是一个函数,只需像这样创建记分器:
my_scorer = make_scorer(adjusted_rsquare, greater_is_better=True)
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您还需要更改得分函数:
def adjusted_rsquare(y_true, y_pred, **kwargs):
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这就是您应该使用的原型。您将实际结果与应有的结果进行比较。
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