当应该影响X的变量发生变化时,变量X不会更新

Question

我是python的初学者.作为大多数初学者,我正在尝试制作基于文本的RPG.我终于得到了升级系统,并且处于另一个障碍.当角色升级时,他们会将x技能点分配给技能(将x添加到变量x次).其中两个变量会影响字符的运行状况,但是,当用户更改这两个变量时,运行状况变量保持不变.我已经简化了我的代码以便于阅读(因为我上面的散文从lol开始并不是那么清楚):

class Char:

    def __init__(self, x, y):
        self.str = x
        self.con = y
        self.hp = (self.con + self.str) / 2


player = Char(20, 20)


def main(dude):
    print("strength:     " + str(dude.str))
    print("constitution: " + str(dude.con))
    print("hp: " + str(dude.hp))
    print("------")
    action = input("press 1 to change str, 2 to change con")
    if action == "1":
        dude.str = dude.str + 10
        main(dude)
    elif action == "2":
        dude.con = dude.con + 10
        main(dude)
    else:
        main(dude)


main(player)

虽然在这种情况下这些变量可以增加10,但hp保持在20

我该如何解决这个问题？

谢谢!

Answer 1

每当Char的属性更新时,代码都需要重新计算HP.
所有这些代码最好放在Char对象中:

class Char:
    def __init__(self, x, y):
        self.str = x
        self.con = y
        self.setHP()

    def __str__(self):
        text = "strength:     " + str(self.str) + "\n" +\
               "constitution: " + str(self.con) + "\n" +\
               "hp:           " + str(self.hp)
        return text

    def setHP(self):
        self.hp = (self.con + self.str) / 2

    def adjustStr(self, amount):
        self.str += amount
        self.setHP()

    def adjustCon(self, amount):
        self.con += amount
        self.setHP()


def main(dude):
    print(str(dude))
    print("------")
    action = input("press 1 to change str, 2 to change con")
    if action == "1":
        dude.adjustStr(10)
        main(dude)
    elif action == "2":
        dude.adjustCon(10)
        main(dude)
    else:
        main(dude)


player = Char(20, 20)

main(player)