Zend选择NOT IN

Eli*_*lie 7 php mysql zend-framework zend-db

我有两个带有相关数据的表,我想从一个表中选择另一个表中不存在的所有记录,加上相关表上的一些其他标准,如下所示(123仅用于说明目的):

TABLE A
    ID
    SOMETHING

TABLE B
    TABLE_A_ID
    TABLE_C_ID
    SOMETHING
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我的查询直接针对数据运行,如下所示

SELECT A.SOMETHING 
    FROM A 
    WHERE A.ID NOT IN (
        SELECT 
            B.TABLE_A_ID AS ID 
            FROM B 
            WHERE TABLE_C_ID = 123
    );
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我如何在Zend中运行它?

Gle*_*rry 17

你可以直接运行sql,使用$db->query(); 你的只是:

$results = $db->query("SELECT A.SOMETHING 
FROM A 
WHERE A.ID NOT IN (
    SELECT 
        B.TABLE_A_ID AS ID 
        FROM B 
        WHERE TABLE_C_ID = ?
)", $id);
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编辑:要回答是否可以使用对象表示法,是:

$sub_select = $zdb->select()
                  ->from("b", array("table_a_id AS id"))
                  ->where("table_c_id = ?", 'a');
$select = $zdb->select()
              ->from("a", array("something"))
              ->where("id NOT IN ?", $sub_select);
print $select->__toString();
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SELECT `a`.`something` FROM `a`
WHERE (id NOT IN
    (SELECT `b`.`table_a_id` AS `id` FROM `b` WHERE (table_c_id = 'a')))
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