Ram*_*amu 5 java json jackson-databind
当尝试将 double 值映射/设置为 0.0 时,ObjectMapper 将其视为等效于 null,从而在比较相等性时排除。
我有以下测试用例:
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.util.Map;
import lombok.Getter;
import lombok.Setter;
import net.javacrumbs.jsonunit.JsonAssert;
import org.junit.Test;
public class ValidJson {
@Getter
@Setter
static class Temp {
Double dblValue;
Integer intVal;
boolean valid = false;
}
@Test
public void validJson() throws Exception {
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setSerializationInclusion(Include.NON_NULL);
objectMapper.setSerializationInclusion(Include.NON_DEFAULT);
String json = "{\"dblValue\":0.0}";
Temp generatedObj = objectMapper.readValue(json, Temp.class);
Map<?, ?> originalJsonMap = objectMapper.readValue(json, Map.class);
JsonNode generatedObjMap = objectMapper.valueToTree(generatedObj);
JsonNode originalObjMap = objectMapper.valueToTree(originalJsonMap);
Assert.assertSame(originalObjMap, generatedObjMap);
}
}
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上面的测试用例因断言错误而失败 java.lang.AssertionError: JSON documents are different: Different keys found in node "". Expected [dblValue], got []. Missing: "dblValue"
但是当我更改String json = "{\"dblValue\":0.0}";as 时String json = "{\"dblValue\":1.0}";,测试通过。
我认为 Double 的默认值行为与 Jackson 一起发生了一些事情,我无法弄清楚并解决我的上述问题。杰克逊 v2.8.10。
这里的问题是:
objectMapper.setSerializationInclusion(Include.NON_DEFAULT);
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双精度值 0.0 被视为默认值,Jackson 忽略它。删除此行后,一切正常。如果您不希望包含boolean valid = false,请为有效字段添加@JsonInclude注释,如下所示:
@JsonInclude(Include.NON_DEFAULT)
boolean valid = false;
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