我正在尝试根据另一列的信息填充一个空列
我的数据框
A B C
0 F House Are you at home?
1 E House description: to deliver tomorrow
2 F Apt Here is some exemples
3 F House description: a brown table
4 E Apt description: in the bus
5 F House Hello, how are you?
6 E Apt description: keys
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所以,我创建一个D列,如果列C以'description'开头,我填写'fuzzy',如果没有'buzzy'.
new_column['D'] = ''
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我试着填补它们
def fill_column(delete_column):
if new_column['D'].loc[new_column['D'].str.startswith('description:'):
new_column['D'] == 'fuzzy'
else:
new_column['D'] == 'buzzy'
return new_column
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我的输出:
File "<ipython-input-41-ec3c1407168c>", line 6
else:
^
SyntaxError: invalid syntax
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好的输出:
A B C D
0 F House Are you at home? buzzy
1 E House description: to deliver tomorrow fuzzy
2 F Apt Here is some exemples buzzy
3 F House description: a brown table fuzzy
4 E Apt description: in the bus fuzzy
5 F House Hello, how are you? buzzy
6 E Apt description: keys fuzzy
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您不需要if-else
这里的语句,您可以使用np.where
以下方法在一行中干净地完成此操作:
df['D'] = np.where(
df['C'].str.startswith('description:'), 'fuzzy', 'buzzy')
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您可以通过一次loc
调用完成此操作,因为您只分配了两个值.
df['D'] = 'buzzy'
df.loc[df['C'].str.startswith('description:'), 'D'] = 'fuzzy'
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或者在评论中使用df.mask
/ df.where
like @jpp建议:
df['D'] = 'buzzy'
df['D'] = df['D'].mask(df['C'].str.startswith('description:'), 'fuzzy')
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最后,使用map
:
m = {True: 'fuzzy', False: 'buzzy'}
df['D'] = df['C'].str.startswith('description:').map(m)
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print(df)
A B C D
0 F House Are you at home? buzzy
1 E House description: to deliver tomorrow fuzzy
2 F Apt Here is some exemples buzzy
3 F House description: a brown table fuzzy
4 E Apt description: in the bus fuzzy
5 F House Hello, how are you? buzzy
6 E Apt description: keys fuzzy
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