sci*_*rer 1 html python jinja2 flask
我想从下拉列表中选择一个值并相应地显示网页。目前,我可以通过在 URL 末尾键入来访问下拉列表中的每个值。我究竟缺少什么?/metadata/table_name1 metadata/table_name2当我在浏览器中输入它时,我就可以访问。但当我从下拉列表中选择该选项时,我无法获取它。下拉列表应重定向到metadata/drop_down_value.
我已经通过打印单独的 url 路由链接进行了测试。通过单击链接,它就可以工作。我需要从下拉列表中选择。
浏览次数:
@app.route('/metadata', methods=['GET', 'POST'])
def metadata():
cols = None
table = None
db_uri = session.get('db_uri', None)
eng = create_engine(db_uri)
insp = reflection.Inspector.from_engine(eng)
tablenames = insp.get_table_names()
form = SelectTableForm()
form.table_name.choices = tablenames
cols = insp.get_columns(table_name=tablenames[0])
eng.dispose()
return render_template('tables.html', cols=cols, table=tablenames[0], form=form)
@app.route('/metadata/<table>', methods=['GET', 'POST'])
def select_table(table):
form = SelectTableForm()
db_uri = session.get('db_uri', None)
eng = create_engine(db_uri)
insp = reflection.Inspector.from_engine(eng)
tablenames = insp.get_table_names()
form.table_name.choices = tablenames
cols = insp.get_columns(table_name=table)
return render_template('tables.html', cols=cols, table=table, form=form)
Run Code Online (Sandbox Code Playgroud)
形式:
class SelectTableForm(FlaskForm):
table_name = SelectField(label='Table name', choices=[], coerce=int)
Run Code Online (Sandbox Code Playgroud)
金贾 html:
<!-- This works -->
{% for table in form.table_name.choices %}
<a href="{{ url_for('select_table', table=table) }}">{{ table }}</a>
{% endfor %}
<!-- This does not -->
<form action="">
<select name="tables" method="POST" type="submit">
{% for table in form.table_name.choices %}
<option value="{{ url_for('select_table', table=table) }}">{{ table }}</option>
{% endfor %}
</select>
</form>
<table>
<tr>
<th>table</th>
<th>name</th>
<th>type</th>
<th>nullable</th>
<th>default</th>
<th>autoincrement</th>
<th>comment</th>
</tr>
{% for col in cols %}
<tr>
<td>{{ table }}</td>
{% for val in col.values() %}
<td>{{ val }}</td>
{% endfor %}
</tr>
{% endfor %}
</table>
Run Code Online (Sandbox Code Playgroud)
您需要一些 js,将当前页面的 url 设置为 select 元素中所选选项的值:onchange="location = this.value;"。
from flask import Flask, render_template_string
app = Flask(__name__)
@app.route('/')
def homepage():
return render_template_string('''
<select name="form" onchange="location = this.value;">
{% for table in tables %}
<option value="{{ url_for('select_table', table=table) }}">{{ table }}</option>
{% endfor %}
</select>
''', tables = ['a', 'b'])
@app.route('/select_table/<table>', methods=['GET', 'POST'])
def select_table(table):
return table
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2622 次 |
| 最近记录: |