我试图在下面的多个连接中包含上一个查询中其他表的结果:
SELECT mid as mID,
round((x.qty_sum / x.qty_count), 5) as qtAVG,
round(x.qty_stddev, 5) as qtSTDDEV,
x.qty_count as qtCOUNT,
round((x.rel_sum / x.rel_count), 5) as relAVG,
round(x.rel_stddev, 5) as relSTDDEV,
x.rel_count as relCOUNT,
FROM (SELECT t.mid,
SUM( mt = 'qt' ) as qty_count,
SUM(CASE WHEN t_r.mt = 'qt' THEN rt END) as qty_sum,
STD(CASE WHEN t_r.mt = 'qt' THEN rt END) as qty_stddev,
SUM( t_r.mt = 'rel' ) as rel_count,
SUM(CASE WHEN t_r.mt = 'rel' THEN rel END) as rel_sum,
STD(CASE WHEN t_r.mt = 'rel' THEN rel END) as rel_stddev
FROM t_r r
right join t_m t on t.mid = r.mid
right join m_k m on m.mid = t.mid
right join k_d k on m.kid = k.kid
GROUP BY t.mid
) x;
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用我上面的查询,qty_count为111当mt是qt回报6,而不是2.2 * (count of 111 in table m_k)
当我删除的加入这部分,我得到了想要的金额qtCOUNT和relCOUNT
right join m_k m on m.mid = t.mid
right join k_d k on m.kid = k.kid
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我做错了什么,我该如何解决?
数据:
m_k
mid kid
--------
109 2
110 2
110 4
111 1
111 2
111 3
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K_D
kid k_desc
-----------
1 desc1
2 desc2
3 desc3
4 desc4
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M_D
mid col1 col2 col3 col4
-------------------------------
109 val_a val_d val_g val_j
110 val_b val_e val_h val_k
111 val_c val_f val_i val_l
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T_R
mid rt stamp mt
----------------------------------
111 3 2018-12-08 01:30:31 rel
111 4 2018-12-08 03:41:56 qt
111 3 2018-12-08 02:29:10 qt
110 1 2018-12-08 06:13:51 rel
110 5 2018-12-08 11:44:39 qt
109 1 2018-12-08 10:39:51 rel
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其他与上述相同的查询都可以.
我通过移动解决了这个问题
right join m_k m on m.mid = t.mid
right join k_d k on m.kid = k.kid
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在派生表之外x.最终查询如下所示:
SELECT mid as mID,
round((x.qty_sum / x.qty_count), 5) as qtAVG,
round(x.qty_stddev, 5) as qtSTDDEV,
x.qty_count as qtCOUNT,
round((x.rel_sum / x.rel_count), 5) as relAVG,
round(x.rel_stddev, 5) as relSTDDEV,
x.rel_count as relCOUNT,
FROM (SELECT mid,
SUM( mt = 'qt' ) as qty_count,
SUM(CASE WHEN mt = 'qt' THEN rt END) as qty_sum,
STD(CASE WHEN mt = 'qt' THEN rt END) as qty_stddev,
SUM( mt = 'rel' ) as rel_count,
SUM(CASE WHEN mt = 'rel' THEN rel END) as rel_sum,
STD(CASE WHEN mt = 'rel' THEN rel END) as rel_stddev
FROM t_r r
right join t_m t on t.mid = r.mid
GROUP BY mid
) x
right join m_k m on m.mid = x.mid
right join k_d k on k.kid = m.kid
group by m.mid;
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