android 房间中实体中不存在主键,复合键

Val*_*kef 3 database android primary-key composite-primary-key android-room

我得到的错误是:

错误:实体中不存在主键中引用的主题 ID、图片 ID。可用列名:theme_id、picture_id、image

我在网上广泛查看,但我找不到任何关于此的信息。这个错误似乎只有在尝试使用复合键时才会出现。如果我用普通的 PrimaryKey 注释其中一个字段,它就可以正常工作。我不明白这里发生了什么,令人沮丧的是我在网上找不到任何关于此的信息。我希望你们能帮助我。

实体

@Entity(primaryKeys = {"theme_id, picture_id"}, tableName = "picture")
public class Picture {

    @ColumnInfo(name = "theme_id")
    private int themeId;
    @ColumnInfo(name = "picture_id")
    private int pictureId;
    @ColumnInfo(name = "image", typeAffinity = ColumnInfo.BLOB)
    private byte[] image;
}
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@Dao
public interface PictureDao {

    @Insert
    void instertPictures(Picture... pictures);

    @Update
    void updatePictures(Picture... pictures);

    @Delete
    void deletePictures(Picture... pictures);

    @Query("SELECT * FROM picture")
    List<Picture> getAllPictures();

    @Query("SELECT * FROM picture WHERE theme_id = :themeId")
    List<Picture> getThemePictures(int themeId);

    @Query("SELECT * FROM picture WHERE theme_id = :themeId AND picture_id = :pictureId")
    Picture getPicture(int themeId, int pictureId);

}
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数据库

@Database(entities = {Picture.class}, version = 1, exportSchema = false)
public abstract class PictureDatabase extends RoomDatabase {

    public static final String NAME = "picture_db";

    public abstract PictureDao pictureDao();
}
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Dom*_*min 6

您收到此错误,因为您尚未创建名为theme_id, picture_id. 可能你的意思是有 2 个主键theme_idpicture_id. 然后你必须传递两个用逗号分隔的字符串,而不是一个用逗号分隔的字符串。

所以改变

{"theme_id, picture_id"}
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 "  only one string   "
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{"theme_id", "picture_id"}
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 " first  ", "  second  "
 " string "  "  string  "
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它应该可以正常工作。