jal*_*mer 0 javascript arrays filter promise
我编写了一个函数来从数组中过滤时间间隔。该功能似乎可以工作,并且打印跳过和接受是适当的并且没有打印错误。但是,它会产生一个空数组。
getDate()
是一个返回日期的函数,因此可以使用 将其解析为时间getTime()
。这样可行。
async function getInterval(climatedata,harvestdate,period) {
return new Promise(function(resolve, reject) {
getDate(harvestdate,-1*period).then((sval)=>{
let start = sval.getTime();
getDate(harvestdate,0).then(async(eval)=>{
let end = eval.getTime();
let filtered = await Promise.all(climatedata.filter((curVal,index,arr) => {
getDate(curVal[0]).then((tval)=>{
let td = tval.getTime();
//console.log(start,td,end);
if(td >= start && td <= end) {
console.log("accept"); //although this is printed for the expected subset, nothing is in the filtered array.
return true;
} else {
//console.log("skip");
return false;
}
}).catch((err)=>{console.log(err);});
}));
console.log("filtered",filtered); //here I would expect an array with some rows.
//console.log("bef",climatedata.length,"aft",filtered.length); //this is always bef 8000 aft 0
resolve(filtered);
});
});
});
}
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我也尝试过使用一个小的变体.then() on Promise.all
,但没有成功。
我究竟做错了什么?谢谢你,延斯
因此,您的代码存在一些问题。
首先,你的实际问题。请注意,filter
返回一个新数组,其中包含通过测试函数的元素。要通过测试函数,该函数迭代中返回的任何真值都意味着数组中该索引处的项目应该通过。所以你有了:
await Promise.all(climatedata.filter((curVal,index,arr) => {
getDate(curVal[0])...
};
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您面临的第一个直接问题是您在过滤器的回调函数中没有返回任何内容,这意味着您undefined
在过滤器的每次迭代中都返回。undefined == false
,因此该迭代的测试未通过。由于没有一个测试通过,你真正最终得到的是:
await Promise.all([undefined, undefined, ...])
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这确实会解析为undefined
.
现在我们已经解决了这个问题,让我们清理一下你的代码。首先,既然您正在使用async
,那么您几乎永远不需要使用new Promise
。将函数标记为async
隐式包装它在承诺中返回的任何内容,这意味着您不需要这样做。
// NOTE: I've removed your console.log statements to make it simpler to read
async function getInterval(climatedata,harvestdate,period) {
return getDate(harvestdate,-1*period).then((sval)=>{
let start = sval.getTime();
getDate(harvestdate,0).then(async(eval)=>{
let end = eval.getTime();
let filtered = await Promise.all(climatedata.filter((curVal,index,arr) => {
return getDate(curVal[0]).then((tval)=>{ // NOTICE: I added `return` here to beging to fix your filter problem
let td = tval.getTime();
if(td >= start && td <= end) {
return true;
} else {
return false;
}
}).catch((err)=>{console.log(err);});
}));
return filtered;
});
});
}
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好吧,接下来,既然你在async
世界上,你永远不需要使用.then
or .catch
:
async function getInterval(climatedata, harvestdate, period) {
let sval;
try {
sval = await getDate(harvestdate, -1 * period);
} catch (error) {
console.log('getting `sval` failed, oh no!');
throw error;
}
let start = sval.getTime();
let eval;
try {
eval = await getDate(harvestdate, 0);
} catch (error) {
console.log('getting `eval` failed, oh no!');
throw error;
}
let end = eval.getTime();
let filtered = await Promise.all(climatedata.filter(async (curVal,index,arr) => {
let tval;
try {
tval = getDate(curVal[0]);
} catch (error) {
console.log('getting `tval` failed, oh no!');
throw error;
}
let td = tval.getTime();
if(td >= start && td <= end) {
return true;
} else {
return false;
}
}));
return filtered;
}
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好多了。但是好吧,让我们再次讨论您的问题的核心:您想要过滤掉承诺列表。这意味着您不仅可以使用filter
,还需要使用filter
and map
:
async function getInterval(climatedata, harvestdate, period) {
let sval;
try {
sval = await getDate(harvestdate, -1 * period);
} catch (error) {
console.log('getting `sval` failed, oh no!');
throw error;
}
let start = sval.getTime();
let eval;
try {
eval = await getDate(harvestdate, 0);
} catch (error) {
console.log('getting `eval` failed, oh no!');
throw error;
}
let end = eval.getTime();
const filterTest = (curVal, index, arr)
const climatedataPromises = climatedata.map(curVal => getDate(curVal[0])); // Create a list of promises
const climatedata = await Promise.all(climatedataPromises); // Wait for them all to return
return climatedata.filter((tval, index) => { // Now run your filter
let td = tval.getTime();
if(td >= start && td <= end) {
return true;
} else {
return false;
}
});
}
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享受 :)
*我不保证我不会在某个地方缺少右括号或括号:)