通过多个分隔符拆分列,保留分隔符

Nea*_*sch 6 regex r strsplit data.table

如何使用 %、- 和 + 作为可能的分隔符将字符列拆分为 3 列,并将分隔符保留在新列中?

示例数据:

data <- data.table(x=c("92.1%+100-200","90.4%-1000+200", "92.8%-200+100", "99.2%-500-200","90.1%+500-200"))
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所需数据示例:

data.desired <- data.table(x1=c("92.1%", "90.4%", "92.8%","99.2%","90.1%")
                           , x2=c("+100","-1000","-200","-500","+500")
                           , x3=c("-200","+200","+100","-200","-200"))
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很高兴为一个好的答案和对这个问题的一些帮助奖励积分!

Jul*_*ora 6

我们可以使用separatefromtidyr进行分割,并使用正向前瞻来保留分隔符:

data %>% separate(x, c("x1", "x2", "x3"), sep = "(?=\\+|-)")
#       x1    x2   x3
# 1: 92.1%  +100 -200
# 2: 90.4% -1000 +200
# 3: 92.8%  -200 +100
# 4: 99.2%  -500 -200
# 5: 90.1%  +500 -200
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也就是说,请注意,简单地拆分\\+|-我们会得到

data %>% separate(x, c("x1", "x2", "x3"), sep = "\\+|-")
#       x1   x2  x3
# 1: 92.1%  100 200
# 2: 90.4% 1000 200
# 3: 92.8%  200 100
# 4: 99.2%  500 200
# 5: 90.1%  500 200
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在“无”处使用(?=\\+|-)split 以防紧接着我们有+or -(不匹配)。


the*_*ail 5

data.table等价的是tstrsplit

data[, c("x1","x2","x3") := tstrsplit(x, "(?<=.)(?=[+-])", perl=TRUE) ]
data
#                x    x1    x2   x3
#1:  92.1%+100-200 92.1%  +100 -200
#2: 90.4%-1000+200 90.4% -1000 +200
#3:  92.8%-200+100 92.8%  -200 +100
#4:  99.2%-500-200 99.2%  -500 -200
#5:  90.1%+500-200 90.1%  +500 -200
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