Nea*_*sch 6 regex r strsplit data.table
如何使用 %、- 和 + 作为可能的分隔符将字符列拆分为 3 列,并将分隔符保留在新列中?
示例数据:
data <- data.table(x=c("92.1%+100-200","90.4%-1000+200", "92.8%-200+100", "99.2%-500-200","90.1%+500-200"))
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所需数据示例:
data.desired <- data.table(x1=c("92.1%", "90.4%", "92.8%","99.2%","90.1%")
, x2=c("+100","-1000","-200","-500","+500")
, x3=c("-200","+200","+100","-200","-200"))
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很高兴为一个好的答案和对这个问题的一些帮助奖励积分!
我们可以使用separate
fromtidyr
进行分割,并使用正向前瞻来保留分隔符:
data %>% separate(x, c("x1", "x2", "x3"), sep = "(?=\\+|-)")
# x1 x2 x3
# 1: 92.1% +100 -200
# 2: 90.4% -1000 +200
# 3: 92.8% -200 +100
# 4: 99.2% -500 -200
# 5: 90.1% +500 -200
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也就是说,请注意,简单地拆分\\+|-
我们会得到
data %>% separate(x, c("x1", "x2", "x3"), sep = "\\+|-")
# x1 x2 x3
# 1: 92.1% 100 200
# 2: 90.4% 1000 200
# 3: 92.8% 200 100
# 4: 99.2% 500 200
# 5: 90.1% 500 200
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在“无”处使用(?=\\+|-)
split 以防紧接着我们有+
or -
(不匹配)。
data.table
等价的是tstrsplit
:
data[, c("x1","x2","x3") := tstrsplit(x, "(?<=.)(?=[+-])", perl=TRUE) ]
data
# x x1 x2 x3
#1: 92.1%+100-200 92.1% +100 -200
#2: 90.4%-1000+200 90.4% -1000 +200
#3: 92.8%-200+100 92.8% -200 +100
#4: 99.2%-500-200 99.2% -500 -200
#5: 90.1%+500-200 90.1% +500 -200
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