在尝试做类似于Alex Martelli 的ActiveState配方标题为Python中的Constants时,我遇到了意外的副作用(在Python 2.7中),它将类实例分配给sys.moduleshas中的一个条目- 即显然这样做更改__name__to 的值,None如下面的代码片段所示(它会破坏配方中的部分代码):
class _test(object): pass
import sys
print '# __name__: %r' % __name__
# __name__: '__main__'
sys.modules[__name__] = _test()
print '# __name__: %r' % __name__
# __name__: None
if __name__ == '__main__': # never executes...
import test
print "done"
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我想知道为什么会这样.我不相信它在Python 2.6和早期版本中是这样的,因为我有一些较旧的代码,显然if __name__ == '__main__':条件在赋值后按预期工作(但不再有).
FWIW,我也注意到这个名字在分配后也会_test从一个类对象反弹None回来.我觉得很奇怪他们正在反弹None而不是完全消失......
更新:
我想补充一点,任何实现效果的变通办法if __name__ == '__main__':都会受到高度赞赏.TIA!
mou*_*uad 29
发生这种情况是因为你sys.modules[__name__] = _test()删除模块时你已经覆盖你的模块(因为模块没有任何对它的引用,并且引用计数器变为零,所以它被删除了)但是同时解释器仍然有字节代码,所以它仍然可以工作,但返回None到模块中的每个变量(这是因为python None在删除时将所有变量设置在模块中).
class _test(object): pass
import sys
print sys.modules['__main__']
# <module '__main__' from 'test.py'> <<< the test.py is the name of this module
sys.modules[__name__] = _test()
# Which is the same as doing sys.modules['__main__'] = _test() but wait a
# minute isn't sys.modules['__main__'] was referencing to this module so
# Oops i just overwrite this module entry so this module will be deleted
# it's like if i did:
#
# import test
# __main__ = test
# del test
# __main__ = _test()
# test will be deleted because the only reference for it was __main__ in
# that point.
print sys, __name__
# None, None
import sys # i should re import sys again.
print sys.modules['__main__']
# <__main__._test instance at 0x7f031fcb5488> <<< my new module reference.
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编辑:
修复将是这样做的:
class _test(object): pass
import sys
ref = sys.modules[__name__] # Create another reference of this module.
sys.modules[__name__] = _test() # Now when it's overwritten it will not be
# deleted because a reference to it still
# exists.
print __name__, _test
# __main__ <class '__main__._test'>
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希望这能解释一切.