获取MySQL表中的第二高值

Question

我有一个员工和工资表,用这种方式定义:

"name" (type: VARCHAR)
"salary" (type: INTEGER)

我可以使用什么查询来获得此表中第二高的薪水？

Answer 1

这是一个解释关系的人.

Name    Salary
Jim       6
Foo       5
Bar       5
Steve     4

SELECT name, salary
FROM employees
WHERE salary = (SELECT MAX(salary) FROM employees WHERE salary < (SELECT MAX(salary) FROM employees))

Result --> Bar 5, Foo 5

编辑: 我拿了Manoj的第二篇文章,调整它,使它更具人性化.对我而言,n-1并不直观; 但是,使用我想要的值,2 = 2nd,3 = 3rd等.

/* looking for 2nd highest salary -- notice the '=2' */
SELECT name,salary FROM employees
WHERE salary = (SELECT DISTINCT(salary) FROM employees as e1
WHERE (SELECT COUNT(DISTINCT(salary))=2 FROM employees as e2
WHERE e1.salary <= e2.salary)) ORDER BY name

Result --> Bar 5, Foo 5

Answer 2

第二高薪的直接答案

SELECT name, salary
FROM employees ORDER BY `employees`.`salary` DESC LIMIT 1 , 1

另一个有趣的方案

SELECT salary 
FROM emp 
WHERE salary = (SELECT DISTINCT(salary) 
                FROM emp as e1 
                WHERE (n) = (SELECT COUNT(DISTINCT(salary)) 
                             FROM emp as e2 
                             WHERE e1.salary <= e2.salary))

Answer 3

似乎我迟到了回答这个问题.这个衬垫如何获得相同的输出？

SELECT DISTINCT salary FROM employees ORDER BY salary DESC LIMIT 1,1 ;

样品小提琴:https://www.db-fiddle.com/f/v4gZUMFbuYorB27AH9yBKy/0

Answer 4

create table svalue (
name varchar(5),
value int
) engine = myisam;

insert into svalue value ('aaa',30),('bbb',10),('ccc',30),('ddd',20);

select * from svalue where value = (
select value 
from svalue
group by value
order by  value desc limit 1,1)

Answer 5

至于第二次:

SELECT name, salary
    FROM employee 
    ORDER BY salary DESC
    LIMIT 1 , 1

至于第三个:

SELECT name, salary
    FROM employee 
    ORDER BY salary DESC
    LIMIT 2 , 1