如何在 plotly 中为子图中的所有图强制使用相同的颜色?

RMa*_*cey 5 r plotly r-plotly

在下面的示例中,我在一个可绘制的子图中有四个箱线图。此示例中的四个箱形图均具有 3 个变量:股票、债券和现金。在每个箱线图中,我希望股票以相同颜色(例如蓝色)显示,债券以相同颜色(例如红色)显示,现金以第三种颜色显示。下面的代码使我有 12 种颜色,而不是 3 种颜色。我做了一个简单的例子。在我的实际问题中,变量的数量将在运行时确定,因此我无法轻松地对颜色进行硬编码。我想调用一个调色板。

library(RColorBrewer)
library(plotly)
set.seed(101)
tbl1y <- data.frame(stocks = rnorm(1000,10,15),
                   bonds = rnorm(1000, 7, 8),
                   cash = rnorm(1000,3,1))
tbl3y <- data.frame(stocks = rnorm(1000,10,15*0.75),
                    bonds = rnorm(1000, 7, 8*0.75),
                    cash = rnorm(1000,3,1*0.75))
tbl5y <- data.frame(stocks = rnorm(1000,10,15*0.5),
                    bonds = rnorm(1000, 7, 8*0.5),
                    cash = rnorm(1000,3,1*0.5))
tbl10y <- data.frame(stocks = rnorm(1000,10,15*0.25),
                    bonds = rnorm(1000, 7, 8*0.25),
                    cash = rnorm(1000,3,1*0.25))

create_1boxplot <- function(tbl, n, vnames){
    mypalette <- brewer.pal(length(vnames), "Dark2")
    p <- plot_ly(data = tbl, type="box")
    for(i in vnames){
        p <- p %>% 
            add_trace(y = tbl[,i], name = i)
    }
    a<-list(text=paste("Boxplot of", n, "Year Returns"),
            xref = "paper",
            yref = "paper",
            yanchor = "bottom",
            xanchor = "center",
            color = vnames,
            colors = mypalette,
            align = "left",
            valign = "top",
            x = 0.5,
            y = 1,
            showarrow = FALSE)
    p <- p %>% layout(annotations=a)
    return(p)
}

vnames <- c("stocks", "bonds", "cash")
p1 <- create_1boxplot(tbl1y, 1, vnames = vnames)
p3 <- create_1boxplot(tbl3y, 3, vnames = vnames)
p5 <- create_1boxplot(tbl5y, 5, vnames = vnames)
p10 <- create_1boxplot(tbl10y, 10, vnames = vnames)

subplot(p1, p3, p5, p10, titleX=FALSE, titleY=FALSE, nrows=2, margin=0.05) %>%
    layout(showlegend = FALSE,
           yaxis = list(title = ""), 
           xaxis = list(title = ""))
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在此处输入图片说明

rma*_*cey 1

可以在这里找到解决方案。简而言之,将brewer.pal函数调用的第一个参数(n)加1;并且,添加到函数中的colorway=mypalette调用。layoutcreate_1boxplot