小智 79
FIXNUM_MAX = (2**(0.size * 8 -2) -1)
FIXNUM_MIN = -(2**(0.size * 8 -2))
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Mat*_*ley 48
Ruby在溢出时自动将整数转换为大整数类,因此(实际上)它们的大小没有限制.
如果您正在寻找机器的大小,即64位或32位,我在ruby-forum.com上找到了这个技巧:
machine_bytes = ['foo'].pack('p').size
machine_bits = machine_bytes * 8
machine_max_signed = 2**(machine_bits-1) - 1
machine_max_unsigned = 2**machine_bits - 1
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如果您正在寻找Fixnum对象的大小(小到足以存储在单个机器字中的整数),您可以调用0.size以获取字节数.我猜它应该是32位版本的4,但我现在无法测试.此外,最大的Fixnum显然是2**30 - 1(或2**62 - 1),因为一位用于将其标记为整数而不是对象引用.
And*_*imm 13
阅读友好的手册?谁想要这样做?
start = Time.now
largest_known_fixnum = 1
smallest_known_bignum = nil
until smallest_known_bignum == largest_known_fixnum + 1
if smallest_known_bignum.nil?
next_number_to_try = largest_known_fixnum * 1000
else
next_number_to_try = (smallest_known_bignum + largest_known_fixnum) / 2 # Geometric mean would be more efficient, but more risky
end
if next_number_to_try <= largest_known_fixnum ||
smallest_known_bignum && next_number_to_try >= smallest_known_bignum
raise "Can't happen case"
end
case next_number_to_try
when Bignum then smallest_known_bignum = next_number_to_try
when Fixnum then largest_known_fixnum = next_number_to_try
else raise "Can't happen case"
end
end
finish = Time.now
puts "The largest fixnum is #{largest_known_fixnum}"
puts "The smallest bignum is #{smallest_known_bignum}"
puts "Calculation took #{finish - start} seconds"
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tom*_*mym 11
在ruby Fixnums中自动转换为Bignums.
要找到最高可能的Fixnum,您可以执行以下操作:
class Fixnum
N_BYTES = [42].pack('i').size
N_BITS = N_BYTES * 8
MAX = 2 ** (N_BITS - 2) - 1
MIN = -MAX - 1
end
p(Fixnum::MAX)
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从一个红宝石谈话讨论中无耻地撕掉了.看那里了解更多细节.