如何打包 .NET Standard NuGet 包而不重建它？

Question

如何打包在 CSProj 文件中具有 Nuget 规范的 .NET Standard NuGet 包而不重建它？

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我有一些自动化需要在构建步骤和打包步骤之间运行，这些自动化与构建过程本身分离，并且不应该是与任何项目相关的构建事件。

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当我尝试使用 nuget CLI 时，它失败并显示以下内容：

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Error NU5012: Unable to find \'bin\\Debug\\LibraryNuGetExample\\bin\\Debug\\\'. Make sure the project has been built.

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这没有任何意义，因为那不是构建输出文件夹！正确的输出文件夹是bin\\Debug\\**——我不明白为什么它要寻找我没有在任何地方指定的目录映射。

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我尝试使用这个，但它重建了，我绝对不想要；只是nuget pack：

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MSBuild LibraryNuGetExample.csproj /t:pack

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所以我要么需要知道如何，

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1. 使用 MSBuid 仅打包而不构建具有某些当前未知选项的包
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2. 使用具有当前未知选项的 NuGet CLI 来打包它
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3. 我还没有考虑过其他一些聪明的事情:)
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LibraryNuGetExample.csproj

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<Project Sdk="Microsoft.NET.Sdk">\n\n  <PropertyGroup>\n    <TargetFrameworks>uap10.0;net45</TargetFrameworks>\n    <PackageId>LibraryForNuGetExample</PackageId>\n    <Authors>user name</Authors>\n    <Company>ACME</Company>\n    <Product>Library For NuGet Example</Product>\n    <Description>A test package to test automation.</Description>\n    <Copyright>ACME \xc2\xa9 2018</Copyright>\n    <PackageTags>DevOps Builds Testing</PackageTags>\n    <PackageVersion>$(AssemblyVersion)</PackageVersion>\n    <Platforms>x64;AnyCPU</Platforms>\n    <NeutralLanguage>en-US</NeutralLanguage>\n  </PropertyGroup>\n\n  <PropertyGroup Condition="\'$(TargetFramework)\' == \'uap10.0\'">\n    <NugetTargetMoniker>UAP,Version=v10.0</NugetTargetMoniker>\n    <TargetPlatformIdentifier>UAP</TargetPlatformIdentifier>\n    <TargetPlatformVersion>10.0.15063.0</TargetPlatformVersion>\n    <TargetPlatformMinVersion>10.0.15063.0</TargetPlatformMinVersion>\n    <TargetFrameworkIdentifier>.NETCore</TargetFrameworkIdentifier>\n    <TargetFrameworkVersion>v5.0</TargetFrameworkVersion>\n    <DefineConstants>$(DefineConstants);WINDOWS_UWP</DefineConstants>\n    <LanguageTargets>$(MSBuildExtensionsPath)\\Microsoft\\WindowsXaml\\v$(VisualStudioVersion)\\Microsoft.Windows.UI.Xaml.CSharp.targets</LanguageTargets>\n  </PropertyGroup>\n\n   <ItemGroup>\n    <None Include="LibraryForNuGetExample.targets" Pack="true" PackagePath="build\\uap10.0" />\n  </ItemGroup>\n\n  <ItemGroup Condition=" \'$(TargetFramework)\' == \'uap10.0\' ">\n    <PackageReference Include="Microsoft.NETCore.UniversalWindowsPlatform " Version="5.2.2" />\n  </ItemGroup>\n\n  <ItemGroup>\n    <Reference Include="Windows">\n      <HintPath>C:\\Program Files (x86)\\Windows Kits\\10\\UnionMetadata\\10.0.15063.0\\Windows.winmd</HintPath>\n      <IsWinMDFile>true</IsWinMDFile>\n      <Private>true</Private>\n    </Reference>\n  </ItemGroup>\n\n  <Target Name="CopyPackage" AfterTargets="Pack" Condition="\'$(IsCrossTargetingBuild)\' == \'true\'">\n    <Copy SourceFiles="$(OutputPath)$(PackageId).$(PackageVersion).nupkg" DestinationFolder="$(SolutionDir)Packages" />\n  </Target>\n\n</Project>\n

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LibraryForNuGetExample.targets

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<?xml version="1.0" encoding="utf-8" ?>\n<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">\n  <ItemGroup Condition="\'$(TargetPlatformIdentifier)\' == \'UAP\'">\n    <ReferenceCopyLocalPaths>\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\uap10.0\\LibraryNuGetExample.dll"\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\uap10.0\\LibraryNuGetExample.pdb"\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\uap10.0\\LibraryNuGetExample.pri"\n    </ReferenceCopyLocalPaths>\n  </ItemGroup>\n  <ItemGroup Condition="\'$(TargetPlatformIdentifier)\' == \'NET45\'">\n    <ReferenceCopyLocalPaths>\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\net45\\LibraryNuGetExample.dll"\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\net45\\LibraryNuGetExample.pdb"\n        Include="$(MSBuildThisFileDirectory)bin\\Release\\net45\\LibraryNuGetExample.pri"\n    </ReferenceCopyLocalPaths>\n  </ItemGroup>\n</Project>\n

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Answer 1

您可以使用相当于

dotnet pack --no-build

对于 MSBuild（因为您正在为 UAP 构建）是

msbuild -t:Pack -p:NoBuild=true