differentiating scipy.interpolate.interp1d

Question

Given a two vectors x and y I can use scipy.interpolate.interp1d to compute the (quadratic) spline. However I'm not directly interested in the spline itself, but rather in the derivative of the spline. I would prefer having an explicit solution rather than a numerical derivative.

但是我找不到多项式参数存储在哪里interp1d。我尝试过interp1d.__dict__，其中包含interp1d._spline但我没有找到该参数的定义是什么。

Answer 1

检查InterpolatedUnivariateSpline，它有derivative 方法： 请注意，为了方便起见，导数返回另一个样条对象，并且您还可以指定导数的阶数（默认为 1）。

from scipy.interpolate import InterpolatedUnivariateSpline as IUS
import numpy as np
import matplotlib.pyplot as plt

x = np.arange(10)
y = x**2 + np.random.normal(size=10)

u = IUS(x,y)
u_der = u.derivative()

plt.plot(x, y, 'go')
plt.plot(x, u(x), 'b--')
plt.plot(x, u_der(x), 'k')