我有两个 pytorch 张量:
X 有形状 (A, B, C, D)I 有形状 (A, B)中的值I是范围内的整数[0, C)。
获得Yshape张量的最有效方法是什么(A, B, D),例如:
Y[i][j][k] = X[i][j][ I[i][j] ][k]
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您可能想要torch.gather用于索引并expand调整I到所需的大小:
eI = I[..., None, None].expand(-1, -1, 1, X.size(3)) # make eI the same for the last dimension
Y = torch.gather(X, dim=2, index=eI).squeeze()
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测试代码:
A = 3
B = 4
C = 5
D = 7
X = torch.rand(A, B, C, D)
I = torch.randint(0, C, (A, B), dtype=torch.long)
eI = I[..., None, None].expand(-1, -1, 1, X.size(3))
Y = torch.gather(X, dim=2, index=eI).squeeze()
# manually gather
refY = torch.empty(A, B, D)
for i in range(A):
for j in range(B):
refY[i, j, :] = X[i, j, I[i,j], :]
(refY == Y).all()
# Out[]: tensor(1, dtype=torch.uint8)
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