Matplotlib 动画：如何动态扩展 x 限制？

Question

我有一个简单的动画情节，如下所示：

import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation

# First set up the figure, the axis, and the plot element we want to animate
fig = plt.figure()
ax = plt.axes(xlim=(0, 100), ylim=(0, 100))
line, = ax.plot([], [], lw=2)

x = []
y = []


# initialization function: plot the background of each frame
def init():
    line.set_data([], [])
    return line,


# animation function.  This is called sequentially
def animate(i):
    x.append(i + 1)
    y.append(10)
    line.set_data(x, y)
    return line,


# call the animator.  blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, init_func=init,
                               frames=200, interval=20, blit=True)

plt.show()

现在，这可以正常工作，但我希望它像http://www.roboticslab.ca/matplotlib-animation/中的子图之一一样扩展，其中 x 轴动态扩展以容纳传入的数据点。

我该如何实现？

Answer 1

我遇到了这个问题（但对于 set_ylim ），我对 @ImportanceOfBeingErnest 的评论进行了一些尝试和错误，这就是我得到的，适应@nz_21问题。

def animate(i):
    x.append(i + 1)
    y.append(10)
    ax.set_xlim(min(x), max(x)) #added ax attribute here
    line.set_data(x, y)

    return line, 

# call the animator.  blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, init_func=init,
                               frames=500, interval=20)

其实@nz_21引用的网上也 有类似的解决方案。