SQL返回特定行的rownum？(使用Oracle db)

Question

在Oracle 10g中,我有这个SQL:

select dog.id as dogId from CANINES dog order by dog.codename asc

返回:

id
--
204
203
206
923

我想扩展此查询以确定此结果集中dog.id的oracle rownum.

我试过了

select rownum from 
(select dog.id as dogId from CANINES dog order by dog.codename asc) 
where dog.id=206

但这不是很好(无论哪匹狗都会返回1.我匹配).我本以期待回来3.

谢谢你的帮助!

---

笔记

http://www.oracle.com/technology/oramag/oracle/06-sep/o56asktom.html

我很确定我不需要使用rowid

Answer 1

我怀疑你想要的是使用分析函数(RANK DENSE_RANK,,或ROW_NUMBER),即

SELECT rnk
  FROM (select dog.id as dogId,
               ROW_NUMBER() OVER( ORDER BY dog.codename ASC ) rnk
          from CANINES dog )
 WHERE dogId = 206

如果CANINES表中的ID列不是唯一的,则RANK DENSE_RANK,和ROW_NUMBER)将以不同方式处理关系.

如果你想单独使用ROWNUM,

SELECT rn
  FROM (
        SELECT dogId, rownum rn
          FROM (select dog.id as dogId
                  from CANINES dog 
                 order by dog.codename ASC) inner
       ) middle
 WHERE dogId = 206