如何在JS中使用递归在嵌套数组中查找对象

Question

考虑以下深度嵌套的数组：

const array = [
    {
        id: 1,
        name: "bla",
        children: [
            {
                id: 23,
                name: "bla",
                children: [{ id: 88, name: "bla" }, { id: 99, name: "bla" }]
            },
            { id: 43, name: "bla" },
            {
                id: 45,
                name: "bla",
                children: [{ id: 43, name: "bla" }, { id: 46, name: "bla" }]
            }
        ]
    },
    {
        id: 12,
        name: "bla",
        children: [
            {
                id: 232,
                name: "bla",
                children: [{ id: 848, name: "bla" }, { id: 959, name: "bla" }]
            },
            { id: 433, name: "bla" },
            {
                id: 445,
                name: "bla",
                children: [
                    { id: 443, name: "bla" },
                    {
                        id: 456,
                        name: "bla",
                        children: [
                            {
                                id: 97,
                                name: "bla"
                            },
                            {
                                id: 56,
                                name: "bla"
                            }
                        ]
                    }
                ]
            }
        ]
    },
    {
        id: 15,
        name: "bla",
        children: [
            {
                id: 263,
                name: "bla",
                children: [{ id: 868, name: "bla" }, { id: 979, name: "bla" }]
            },
            { id: 483, name: "bla" },
            {
                id: 445,
                name: "bla",
                children: [{ id: 423, name: "bla" }, { id: 436, name: "bla" }]
            }
        ]
    }
];

我如何使用递归通过可能深深嵌套的键来抓取某个对象？我已经尝试过了，但是这不适用于嵌套超过2个级别，然后返回undefined：

const findItemNested = (arr, itemId, nestingKey) => {
    for (const i of arr) {
        console.log(i.id);
        if (i.id === itemId) {
            return i;
        }
        if (i[nestingKey]) {
            findItemNested(i[nestingKey], itemId, nestingKey);
        }
    }
};

结果应为：

const res = findItemNested(array, 959, "children"); >> { id: 959, name: "bla" }

这也许也可以通过使用 .find或仅通过（通过children键）展平数组，但是对我而言，使用递归似乎是最合乎逻辑的解决方案。有人对此有解决方案吗？

提前致谢 ：）。

Answer 1

您可以使用递归reduce：

const array=[{id:1,name:"bla",children:[{id:23,name:"bla",children:[{id:88,name:"bla"},{id:99,name:"bla"}]},{id:43,name:"bla"},{id:45,name:"bla",children:[{id:43,name:"bla"},{id:46,name:"bla"}]}]},{id:12,name:"bla",children:[{id:232,name:"bla",children:[{id:848,name:"bla"},{id:959,name:"bla"}]},{id:433,name:"bla"},{id:445,name:"bla",children:[{id:443,name:"bla"},{id:456,name:"bla",children:[{id:97,name:"bla"},{id:56,name:"bla"}]}]}]},{id:15,name:"bla",children:[{id:263,name:"bla",children:[{id:868,name:"bla"},{id:979,name:"bla"}]},{id:483,name:"bla"},{id:445,name:"bla",children:[{id:423,name:"bla"},{id:436,name:"bla"}]}]}];

const findItemNested = (arr, itemId, nestingKey) => (
  arr.reduce((a, item) => {
    if (a) return a;
    if (item.id === itemId) return item;
    if (item[nestingKey]) return findItemNested(item[nestingKey], itemId, nestingKey)
  }, null)
);
const res = findItemNested(array, 959, "children");
console.log(res);

Answer 2

这应该有效：

function findByIdRecursive(array, id) {
  for (let index = 0; index < array.length; index++) {
    const element = array[index];
    if (element.id === id) {
      return element;
    } else {
      if (element.children) {
        const found = findByIdRecursive(element.children, id);

        if (found) {
          return found;
        }
      }
    }
  }
}

Answer 3

您还可以使用递归，Array.find如下所示

const array=[{id:1,name:"bla",children:[{id:23,name:"bla",children:[{id:88,name:"bla"},{id:99,name:"bla"}]},{id:43,name:"bla"},{id:45,name:"bla",children:[{id:43,name:"bla"},{id:46,name:"bla"}]}]},{id:12,name:"bla",children:[{id:232,name:"bla",children:[{id:848,name:"bla"},{id:959,name:"bla"}]},{id:433,name:"bla"},{id:445,name:"bla",children:[{id:443,name:"bla"},{id:456,name:"bla",children:[{id:97,name:"bla"},{id:56,name:"bla"}]}]}]},{id:15,name:"bla",children:[{id:263,name:"bla",children:[{id:868,name:"bla"},{id:979,name:"bla"}]},{id:483,name:"bla"},{id:445,name:"bla",children:[{id:423,name:"bla"},{id:436,name:"bla"}]}]}];


function findById(arr, id, nestingKey) {
  
  // if empty array then return
  if(arr.length == 0) return
  
  // return element if found else collect all children(or other nestedKey) array and run this function
  return arr.find(d => d.id == id) 
      || findById(arr.flatMap(d => d[nestingKey] || []), id) 
      || 'Not found'
}

console.log(findById(array, 12, 'children'))

console.log(findById(array, 483, 'children'))

console.log(findById(array, 1200, 'children'))