将 CSV 转换为 JSON (JS) 时如何替换字符串中的逗号

Question

我在尝试使用 JS 将客户端提供的 CSV 转换为 JSON 数据时遇到映射问题。CSV 中的一列包含地址数据，其中包含逗号。我尝试过更改分隔符，但由于某种原因，当我阅读 CSV 时，JS 会忽略设置的分隔符并将它们转换为逗号。这意味着将数据转换为 JSON 时的映射不正确。代码和输出如下：-

JS：-

    $(document).ready(function() {
    $.ajax({
        type: "GET",
        url: "result.csv",
        dataType: "text",
        success: function(data) { $("body").append(csvJSON(data));}
     });
});

function csvJSON(csv){

    var lines=csv.split("\n");

    var result = [];

    var headers=lines[0].split(",");

    for(var i=1;i<lines.length;i++){

        var obj = {};
        var currentline=lines[i].split(",");


        for(var j=0;j<headers.length;j++){

            obj[headers[j]] = currentline[j];
        }

        result.push(obj);

    }

    return JSON.stringify(result); 
  }

CSV 数据：-

"type","geometry__type","geometry__coordinates__001","geometry__coordinates__002","properties__name","properties__address","properties__address2","properties__city","properties__state","properties__postal","properties__country","properties__phone","properties__phoneFormatted","properties__email","properties__web"
"Stockist","Point",-110.788,43.4705,"Whitechapel Ltd","Box 11719, 1135 Maple Way","Jackson,","Wyoming","WY",83002,"US",13077399478,"+1 307 739-9478","whitechapel@wyoming.com","www.whitechapel-ltd.com"
"Stockist","Point",103.82705,1.30637,"Thrive Design & Trading","19, Tanglin Road, #03-35","Tanglin Shopping Centre","Singapore",,247909,"Singapore","65-67357333","65-67357333","francis@thrive-products.com.sg",

目前结果：-

   {  
      "type":"Stockist",
      "geometry__type":"Point",
      "geometry__coordinates__001":"-110.788",
      "geometry__coordinates__002":"43.4705",
      "properties__name":"Whitechapel Ltd",
      "properties__address":"\"Box 11719",
      "properties__address2":" 1135 Maple Way\"",
      "properties__city":"\"Jackson",
      "properties__state":"\"",
      "properties__postal":"Wyoming",
      "properties__country":"WY",
      "properties__phone":"83002",
      "properties__phoneFormatted":"US",
      "properties__email":"13077399478",
      "properties__web\r":"+1 307 739-9478"
   },

期望的结果：-

  {  
      "type":"Stockist",
      "geometry__type":"Point",
      "geometry__coordinates__001":"-110.788",
      "geometry__coordinates__002":"43.4705",
      "properties__name":"Whitechapel Ltd",
      "properties__address":"Box 11719, 1135 Maple Way",
      "properties__address2":"Jackson,",
      "properties__city":"Wyoming",
      "properties__state":"WY",
      "properties__postal":"83002",
      "properties__country":"US",
      "properties__phone":"13077399478",
      "properties__phoneFormatted":"+1 307 739-9478",
      "properties__email":"whitechapel@wyoming.com",
      "properties__web":"www.whitechapel-ltd.com"
   },

Answer 1

由于所有值都用引号引起来，因此您应该将 split 参数更改为正则表达式，仅当逗号位于一对引号之外时才进行拆分。

由于数据的格式化方式，您应该记住，您将有许多不必要的转义引号字符串需要清理。但您必须确保不会意外地清除 csv 中已经转义的任何引号。但我认为这些边缘情况就是人们使用预构建库的原因。

编辑

关于我之前的发言。您可能只需删除字符串开头和结尾的引号即可。但我只是想抛出一个免责声明，并说你的结果可能会根据你的数据而有所不同。

const csv=`\"type","geometry__type","geometry__coordinates__001","geometry__coordinates__002","properties__name","properties__address","properties__address2","properties__city","properties__state","properties__postal","properties__country","properties__phone","properties__phoneFormatted","properties__email","properties__web"
"Stockist","Point",-110.788,43.4705,"Dummy address","Box 11719, 1135 Maple Way","Jackson,","Wyoming","WY",83002,"US",12313213213213,"+111111111","dummy ","dummy web address"`

console.log(csvJSON(csv))

function csvJSON(csv){

    var lines=csv.split("\n");

    var result = [];
    
    var commaRegex = /,(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)/g
    
    var quotesRegex = /^"(.*)"$/g

    var headers = lines[0].split(commaRegex).map(h => h.replace(quotesRegex, "$1"));

    for(var i=1;i<lines.length;i++){

        var obj = {};
        var currentline=lines[i].split(commaRegex);


        for(var j=0;j<headers.length;j++){

            obj[headers[j]] = currentline[j].replace(quotesRegex, "$1");
        }

        result.push(obj);

    }
    return result;
    //return JSON.stringify(result); 
  }