Dav*_*ong 11
所以这就是你如何做到的:
NSCalendar *calendar = [NSCalendar currentCalendar];
NSInteger desiredComponents = (NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit);
NSDate *firstDate = ...; // one date
NSDate *secondDate = ...; // the other date
NSDateComponents *firstComponents = [calendar components:desiredComponents fromDate:firstDate];
NSDateComponents *secondComponents = [calendar components:desiredComponents fromDate:secondDate];
NSDate *truncatedFirst = [calendar dateFromComponents:firstComponents];
NSDate *truncatedSecond = [calendar dateFromComponents:secondComponents];
NSComparisonResult result = [truncatedFirst compare:truncatedSecond];
if (result == NSOrderedAscending) {
//firstDate is before secondDate
} else if (result == NSOrderedDescending) {
//firstDate is after secondDate
} else {
//firstDate is the same day/month/year as secondDate
}
Run Code Online (Sandbox Code Playgroud)
基本上,我们采取两个日期,砍掉他们的小时 - 分钟 - 秒位,然后将它们变回日期.然后我们比较那些日期(不再有时间组件;只有日期组件),看看他们如何比较彼此.
警告:键入浏览器但未编译.警告实施者
| 归档时间: |
|
| 查看次数: |
3577 次 |
| 最近记录: |