Python多进程无法pickle opencv videocapture对象

Question

我正在尝试创建一个独立的进程来处理从相机获取的图像。但多处理似乎很难从 opencv 中提取视频捕获模块。任何人都可以建议解决方法吗？我正在使用 python 3.7.1

from multiprocessing import Process
import multiprocessing as mp
import time
import logging
import logging.handlers
import sys

import logging
from enum import Enum
import cv2


class Logger():
    @property
    def logger(self):
        component = "{}.{}".format(type(self).__module__, type(self).__name__)
        #default log handler to dump output to console

        return logging.getLogger(component)



class MyProcess(Logger):

    def __init__(self, ):
        self.process = Process(target = self.run, args=())
        self.exit = mp.Event()
        self.logger.info("initialize class")
        self.capture = cv2.VideoCapture(0)

    def run(self):
        while not self.exit.is_set():

            pass
        print("You exited!")

    def shutdown(self):
        print("Shutdown initiated")
        self.exit.set()


if __name__ == "__main__":
    p = MyProcess()
    p.process.start()
    print( "Waiting for a while")
    time.sleep(3)
    p.shutdown()
    time.sleep(3)
    print("Child process state: {}".format(p.process.is_alive())) 

返回错误具体表示视频捕获对象无法被腌制。

文件“C:\Program Files (x86)\Microsoft Visual Studio\Shared\Anaconda3_64\lib\multiprocessing\reduction.py”，第 60 行，转储 ForkingPickler(file, protocol).dump(obj)

类型错误：无法腌制 cv2.VideoCapture 对象

Answer 1

我不是专家，但我遇到了同样的问题，并以这种方式解决了。

而不是在 init 函数中使用 cv2.VideoCapture(0)

 def __init__(self, ):
    self.process = Process(target = self.run, args=())
    self.exit = mp.Event()
    self.logger.info("initialize class")
    self.capture = cv2.VideoCapture(0)

我将初始化移至运行函数

 def run(self):
    self.capture = cv2.VideoCapture(0)
    while not self.exit.is_set():

这对我有用。或许对你也有帮助