cha*_*Lgn 0 java javafx splash-screen javafx-8
我有一个闪屏:
我需要有进度条的动画(Indeterminate),但它不起作用.
这可能是因为我的线程在我的initilize方法中运行.
public class splashscreenController implements Initializable {
@Override
public void initialize(URL location, ResourceBundle resources) {
new SplashScreen().run();
}
class SplashScreen extends Task {
@Override
public Object call() {
Platform.runLater(new Runnable() {
@Override
public void run()
Parent root = null;
try {
Thread.sleep(3000);
root = FXMLLoader.load(getClass().getResource("../gui/NewUI.fxml"));
} catch (InterruptedException | IOException e) {
e.printStackTrace();
}
Stage stage = new Stage();
stage.initStyle(StageStyle.UNDECORATED);
assert root != null;
Scene scene = new Scene(root, 1280, 720);
stage.setScene(scene);
stage.show();
MainJavaFx.setPrimaryStage(stage);
((Stage) panParent.getScene().getWindow()).close();
}
});
return null;
}
}
}
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您的代码中有2个问题:
new SplashScreen().run();
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A Task不提供在新线程上运行的功能.run在调用线程上执行.
class SplashScreen extends Task {
@Override
public Object call() {
Platform.runLater(new Runnable() {
@Override
public void run() {
// placeholder for parts of your code
longRunningOperation();
guiUpdate();
}
});
return null;
}
}
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即使您在单独的线程上执行此任务,Runnable传递给Platfrom.runLater在JavaFX应用程序线程上执行,并且从此runnable执行长时间运行的操作会冻结GUI.
在后台线程上执行所有长时间运行的操作,并且仅使用Platfrom.runLater.
new Thread(new SplashScreen()).start();
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class SplashScreen extends Task {
@Override
public Object call() throws IOException, InterruptedException {
Thread.sleep(3000);
final Parent root = FXMLLoader.load(getClass().getResource("../gui/NewUI.fxml"));
Platform.runLater(new Runnable() {
@Override
public void run() {
Stage stage = new Stage();
stage.initStyle(StageStyle.UNDECORATED);
Scene scene = new Scene(root, 1280, 720);
stage.setScene(scene);
stage.show();
MainJavaFx.setPrimaryStage(stage);
((Stage) panParent.getScene().getWindow()).close();
}
});
return null;
}
}
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请注意,由于您没有使用提供的功能Task,因此您可以简单地Runnable使用您的类来实现,而不是继承Task.