Matplotlib - 将标签移动到饼图中间

Com*_*ent 6 python matplotlib pandas pie-chart

我的饼图有效,但我注意到实际图表的文本框似乎没有正常工作.它们只是聚集在一起,所以我想知道有没有办法让我将标签移动到白色圆圈的中间位置,旁边是否有匹配的颜色?

crimeTypes = dict(crimeData["Crime type"].value_counts())

crimeType = []
totalAmount = []
numberOfCrimes = 14

for key in sorted(crimeTypes, key=crimeTypes.get, reverse=True):
    crimeType.append(key)
    totalAmount.append(crimeTypes.get(key))

crimeType_sample = crimeType[0:numberOfCrimes]
totalAmount_sample = totalAmount[0:numberOfCrimes]

fig1, ax1 = plt.subplots()
ax1.pie(totalAmount_sample, labels=crimeType_sample, autopct='%1.1f%%', shadow=False, startangle=90)
ax1.axis('equal')  # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(10,10)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.show();
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ALo*_*llz 3

以下是一些用于重现您的问题的示例数据:

样本数据:

import pandas as pd

data = (['Burglary']*50 + ['Arson', 'Theft', 'Violence'] + ['Drugs']*10 + ['Other'] + 
        ['Shoplifting']*4 + ['Harassment']*17 + ['Murder', 'Vehicle Crime']*3 + 
        ['Some other Crimes']*12 + ['Even More Crime', 'And Crime', 'And More Crime']*10)
crimeData = pd.DataFrame(data, columns=['Crime type'])
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这将导致这个情节:

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使用图例

绘图时不要绘制百分比或标签,然后创建放置在侧面的图例:

fig1, ax1 = plt.subplots()

ax1.pie(totalAmount_sample, shadow=False, startangle=90)  # No labels or %s
ax1.axis('equal')  # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(5,5)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)

plt.legend(labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()], 
           bbox_to_anchor=(1,1))

plt.show();
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旋转标签:

创建您的标签并使用rotatelabels=True. 尽管在许多情况下这可能仍然显得狭窄。

fig1, ax1 = plt.subplots()

labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()]
ax1.pie(totalAmount_sample, labels=labels, shadow=False, startangle=90,
        rotatelabels=True)  # No %

ax1.axis('equal')  # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(7,7)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)

plt.show();
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在此输入图像描述