在android中将参数传递给url

Use*_*ser 2 android

我正在开发一个涉及解析的android应用程序.我想在android中将参数传递给url.我该怎么办?

Chi*_*rag 6

请试试这个.

HttpPost postMethod = new HttpPost("your url");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value"));
nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value"));

postMethod.setEntity(new UrlEncodedFormEntity(nameValuePairs));
DefaultHttpClient hc = new DefaultHttpClient();

HttpResponse response = hc.execute(postMethod);
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nameValuePairs用于在url中添加参数.