Val*_*kyi 2 java mysql hibernate
我创建了数据库,它有一个 ENUM 表的引用,我在这个枚举的实体中有异常。
脚本示例:
CREATE TABLE status (
code VARCHAR(40),
status ENUM('not started', 'in progress', 'finished')
);
insert into status (code, status)
values (1, 'not started'),
(2, 'in progress'),
(3, 'finished');
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CREATE TABLE `explorer` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`create_date` datetime DEFAULT NULL,
`query` varchar(255) COLLATE utf8mb4_unicode_520_ci DEFAULT NULL,
`title` varchar(255) COLLATE utf8mb4_unicode_520_ci DEFAULT NULL,
`status_id` int DEFAULT NULL,
PRIMARY KEY (`id`),
FOREIGN KEY (status_id) REFERENCES status(code)
) ENGINE=MyISAM AUTO_INCREMENT=45 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_520_ci;
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因此,在创建表后,我确实为此表自动创建了实体:
探险家:
@Entity
@Table(name = "explorer", schema = "parsebeandeveloper", catalog = "")
public class ExplorerEntity {
private long id;
private Timestamp createDate;
private String query;
private String title;
private Integer statusId;
@Id
@Column(name = "id")
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
@Basic
@Column(name = "create_date")
public Timestamp getCreateDate() {
return createDate;
}
public void setCreateDate(Timestamp createDate) {
this.createDate = createDate;
}
@Basic
@Column(name = "query")
public String getQuery() {
return query;
}
public void setQuery(String query) {
this.query = query;
}
@Basic
@Column(name = "title")
public String getTitle() {
return title;
}
public void setTitle(String title) {
this.title = title;
}
@Basic
@Column(name = "status_id")
public Integer getStatusId() {
return statusId;
}
public void setStatusId(Integer statusId) {
this.statusId = statusId;
}
}
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地位:
@Entity
@Table(name = "status", schema = "parsebeandeveloper")
public class StatusEntity {
private Integer code;
private Object status;
@Basic
@Column(name = "code")
public Integer getCode() {
return code;
}
public void setCode(Integer code) {
this.code = code;
}
@Basic
@Column(name = "status")
public Object getStatus() {
return status;
}
public void setStatus(Object status) {
this.status = status;
}
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}
那,我在控制台中得到了什么:
org.springframework.beans.factory.BeanCreationException:
在类路径资源 [org/springframework/boot/autoconfigure/orm/jpa /HibernateJpaConfiguration.class] 中定义名称为“entityManagerFactory”的 bean 创建时出错:调用 init 方法失败;嵌套 > 异常是 javax.persistence.PersistenceException: [PersistenceUnit: default] 无法构建 Hibernate SessionFactory;嵌套异常是 org.hibernate.MappingException:属性映射的列数错误:com.sb.bean.parser.explorer.model.domain2.StatusEntity.status 类型:> 对象
我想,我确实犯了错误
在创建表中explorer,在字符串中:
FOREIGN KEY (status_id) REFERENCES status(code)
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Status在这种情况下如何正确创建实体或在表之间创建引用?
Hibernate 抱怨它无法映射,StatusEntity.status因为它被声明为Object类型。
您可以将其更改为StringHibernate 应该能够映射到数据库 ENUM 类型的类型。
您还可以将 Java 枚举用于status字段,并使用@Enumerated注释让休眠映射它。