用Python中的字典循环遍历字典列表的正确方法

Question

我有车辆列表和过滤器字典.代码如下:

过滤词典如下:

filters = {
  'make': 'SKODA',
  'model': 'Fabia',
  'fuel': 'Diesel',
  'transmission': '',
  'registration_year': '',
  'price': {'start': 10000, 'stop': 12000}
}

车辆清单如下:

vehicles = [
  {'make': 'AUDI', 'model': 'Q2 Dsl', 'type': '1.6 TDi Sport', 'fuel': 'Diesel', 'mileage': '19896', 'registration_year': '2017', 'transmission': 'Handbediende versnellingsbak', 'price': 17800}, 
  {'make': 'AUDI', 'model': 'A6 SW Dsl', 'type': '2.0 TDi S line', 'fuel': 'Diesel', 'mileage': '87354', 'registration_year': '2013', 'transmission': 'Handbediende versnellingsbak', 'price': 52000},
  {'make': 'SKODA', 'model': 'Fabia', 'type': '1.6 CR TDi GreenLine Active DPF', 'fuel': 'Diesel', 'mileage': '90613', 'registration_year': '2012', 'transmission': 'Handbediende versnellingsbak', 'price': 11000},
  {'make': 'AUDI', 'model': 'A4 SW Dsl', 'type': '2.0 TDi S tronic', 'fuel': 'Diesel', 'mileage': '47402', 'registration_year': '2016', 'transmission': 'Sequentiele bak', 'price': 93000},
  {'make': 'VOLKSWAGEN', 'model': 'Touran', 'type': '1.4 TSI Trendline', 'fuel': 'Essence', 'mileage': '28588', 'registration_year': '2017', 'transmission': 'Handbediende versnellingsbak', 'price': 87000},
  {'make': 'AUDI', 'model': 'A4 Dsl', 'type': '2.0 TDi', 'fuel': 'Diesel', 'mileage': '66053', 'registration_year': '2014', 'transmission': 'Handbediende versnellingsbak', 'price': 62000}
]

因此,我想循环遍历所有车辆和所有过滤器并仅返回与过滤器匹配的车辆.在这种情况下,我应该只得到斯柯达.

我试过pydash图书馆,但没有成功.

我尝试了什么如下:

def filter_item(vehicle):
  vehicles = []
  for key, value in filters.items():
    if key == "price":
      if vehicle[key] > value['start'] and vehicle[key] < value['stop']:
        vehicles.append(vehicle)
    else:
      if vehicle[key] == value:
        vehicles.append(vehicle)
  return vehicles

result = py_.filter(vehicles, lambda x: filter_item(x))

但是在这种情况下,我得到所有带有燃料类型柴油的车辆,但如果我们从0开始,我应该只获得第二辆,因此只有斯柯达.

知道我该怎么办？有没有更好的方法或更清洁的代码来做到这一点？

Answer 1

你需要检查agaist所有过滤条件,这里有一个python内置的例子filter:

def filter_item(vehicle):
    vehicles = []
    for key, value in filters.items():
        if not value: # skip empty filter
            continue
        if key == "price":
            if vehicle[key] > value['start'] and vehicle[key] < value['stop']:
                continue
        else:
            if vehicle[key] == value:
                continue
        return False # no filter matched
    return True


result = filter(filter_item, vehicles)

与pydash:

result = py_.filter(vehicles, filter_item)

注意:传递的回调函数fitler返回true,表示当前值应包含在结果中.