XslCompiledTransform使用UTF-16编码

Question

我有以下代码,我想使用UTF-8编码格式输出xml数据.但它始终以UTF-16输出数据:

        XslCompiledTransform xslt = new XslCompiledTransform();

            xslt.Load(XmlReader.Create(new StringReader(xsltString), new XmlReaderSettings()));

            StringBuilder sb = new StringBuilder();

            XmlWriterSettings writerSettings = new XmlWriterSettings();
            writerSettings.Encoding = Encoding.UTF8;
            writerSettings.Indent = true;

            xslt.Transform(XmlReader.Create(new StringReader(inputXMLToTransform)), XmlWriter.Create(sb, writerSettings));

Answer 1

XML输出将包含基于流编码的标头,而不是设置中指定的编码.由于字符串是16位unicode,编码将是UTF-16.解决方法是禁止标题并自行添加:

writerSettings.OmitXmlDeclaration = true;

然后当你从StringBuilder获得结果时:

string xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\r\n" + sb.ToString();

Answer 2

如果使用a MemoryStream代替StringBuilder,XmlWriter则会尊重您在其中指定的编码XmlWriterSettings,因为MemoryStream它没有像do那样的固有编码StringBuilder.